VDG~VNQ what is the value of x?
1 answer:
You might be interested in
1.
height= 3
length= 5
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
3 x 5 x 4 = 60
We need 60 blocks
2
height= 4
length= 6
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
4 x 6 x 4 = 96
We need 96 blocks
3
height= 2
length= 3
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
2 x 3 x 4 = 24
We need 24 blocks
4
height= 4
length= 8
width= 6
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
4 x 8 x 6 = 192
We need 192 blocks
5
height= 2
length= 6
width= 4
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
2 x 6 x 4 = 48
We need 48 blocks
6
height= 1
length= 5
width= 3
The number of cubes would be the result of the multiplication of the side measures. Doing so, we have:
1 x 5 x 3 = 15
We need 15 blocks
7
9514 1404 393
Answer:
1.63 cm (across the centerline from release)
Step-by-step explanation:
If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...
h(t) = -7cos(2πt/4)
h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm
That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.
__
If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.
