The area of a square region is 529 mi2. What is the perimeter of the region?

Mathematics

2 answers:

Kisachek [45]2 years ago

6 0

Answer:

92 miles

Step-by-step explanation:

The area of a square is Length x Width. All sides of a square are equal in length so length = width. This is the same as saying x = length and x = width so X times X equals the area. X times X is X².

This tells you that X² = 529 mi². X would equal the square root of 529 which is 23. 23 x 23 = 529.

Each side of the square is 23 miles. The perimeter is equal to side 1 plus side 2 plus side 3 plus side 4. Again since it is a square all sides are equal.

This mean you can just take 4 x 23 miles. The perimeter = 92 miles

Ira Lisetskai [31]2 years ago

3 0

Answer:

The perimeter of the region is 92 miles

Step-by-step explanation:

For a given Square

Area = 529 mi²

Now, To find area we use formula

A = (l)²

529 = l²

√529 = l

23 = l

l = 23 miles

Now, To find perimeter of square we use,

P = 4l

P = 4 (23)

P = 92 miles

Thus, The perimeter of the region is 92 miles

-TheUnknownScientist 72

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The table lists how poverty level income cutoffs (in dollars) for a family of four have changed over time. Use the midpoint for

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The poverty level cutoff in 1987 to the nearest dollar was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: $\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$ .

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

$\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)$

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.

Read more about the midpoint segment here:

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