In a parallelogram opposite sides are equal and parallel;
Therefore, in this case, AB is equal and parallel to CD, thus, the magnitude of AB is equal to the magnitude of CD
The line BC is equal to line AD and the two lines are parallel to y-axis;
Since; AB = B - A = (0,4) - (-3,2)= (2,3)
Assuming the coordinates of D is (x,y) DC= (4-y), (3-x) = (2,3)
Hence; y = 2 and x = 0
Thus; the coordinates of D are (0,2)
Given:
In △ABC is a right angle triangle.
AC is 6 units longer than side BC.

To find:
The length of AC.
Solution:
Let the length of BC be x.
So, Length of AC = x+6
According to the Pythagoras theorem, in a right angle triangle

△ABC is a right angle triangle and AC is hypotenuse, so

![[\because (a+b)^2=a^2+2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D)
Subtract 68 from both sides.



Divide both sides by 2.

Splitting the middle term, we get




Side cannot be negative, so x=2 only.
Now,



Therefore, the length of AC is 8 units.
Answer: Hello, 6
Therefore, the tenths value of 3.629 remains 6. The following table contains starting numbers close to 3.629 rounded to the nearest 10th.
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Step-by-step explanation:
1/5 of the class you multiply the fractions and simplify it
Floor(0) -3 = -3 . . . . . only the left-side graphs have this point
floor(0.1) -3 = -3 . . . . only the lower-left graph has this point.
The lower-left selection is appropriate.