We need to find the lowest common multiple of 8 and 12.
Reminder that the LCM is the lowest number that divides evenly with both of the given numbers.
We can make a chart and see that:
Multiples of 8: 8, 16, 24, 32
Multiples of 12: 12, 24...wait! We have a match with 24!
Therefore, there will be 24 more games until both events will occur.
Answer:
<u>We need to buy 3 cases of juice.</u>
Correct statement and question:
No. of diners = 240 Portions of juice served = 4 oz. per diner Size of juice can = 48 oz. How many cases of juice required if there are 8 cans in a case and you must buy a whole case?
Source:
Previous question that you can search at brainly
Step-by-step explanation:
Let's calculate the number of cases of juice are required this way:
Number of cases required = [(Number of dinners * portion of juice served)/Size of juice can]/Cans in a case
Replacing with the real values, we have:
Number of cases required = [(240 * 4)/48]/8
Number of cases required = [(960)/48]/8
Number of cases required = 20/8
Number of cases required = 2.5
<u>But let's remember that we must buy only whole cases, then we need to buy 3 cases of juice.</u>
4 buses and 167 students
1 bus just 7 students
4x7 = 28
28 students are on 4 buses
167- 28 = 138
138 students had travel in cars
-4 left
+5 up - 1
Your welcome!
Answer:
2.
a) X=5.0791
(sorry I only know that one)