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sladkih [1.3K]
3 years ago
15

Which number can you add to any rational number to obtain an irrational number?

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
I think any irrational number would do this? I'm not positive though. Some examples may be pi or the square root of 2.
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Lewis is planning a cycling holiday.
galben [10]

Answer:

72 miles/day

Step-by-step explanation:

12 m/hr  *  6 hr / day  = 72 mi/day

8 0
2 years ago
MANUFACTURING
Margaret [11]

Answer:

Total cost is $205328

Step-by-step explanation:

Given data:

cost C(q) = 0.1 q^3 - 0.5 q^2 + 500 q + 200

current units q = 4 ( 4000 units )

The current level of production is 4000 ( 4 )units, and manufacturer is planning to upgrade this to 4100 ( 4.1 ) units

C'(q) = 3 * 0.1 q^2 - 2 * 0.5 q + 500

C'(q) = 0.3 q2 - q + 500

C(4.1) - C(4) ≈ C’(4) x Δq

≈ C’(4) x 0.1

≈ ( 0.3 * 4^2 - 4 + 500 ) x 0.1

≈    (  0.3 * 16 - 4 + 500 ) x 0.1

≈    500.8 x 0.1 ≈      50.08

total cost = 4100 x   50.08 = $205328

3 0
3 years ago
2x=24−2 Find value of x​
Alja [10]

Answer:

\sf\longmapsto \: x = 11

Step-by-step explanation:

\sf\longmapsto \: 2x = 24 - 2

\sf\longmapsto \: 2x = 22

\sf\longmapsto \: x =  \frac{22}{2}

\sf\longmapsto \: x = 11

6 0
3 years ago
Read 2 more answers
Scenario: There are 60 boys and 72 girls in a school. The principal wants to divide the students into gender-specific groups (al
mr_godi [17]

Answer: Hence, the correct size of boys group is 5 and girls is 6.

Step-by-step explanation:

Since we have given that

Number of boys = 60

Number of girls = 72

We need to divide the students into gender specific groups of the largest possible size.

For this we will find "HCF of 60 and 72" which is equal to "12".

So, the correct size of each group is 12 in which number of boys would be \dfrac{60}{12}=5

Number of girls would be \dfrac{72}{12}=6

Hence, the correct size of boys group is 5 and girls is 6.

3 0
3 years ago
What type of triangle has these side lengths
cricket20 [7]

Answer:

Option (C)

Step-by-step explanation:

Given sides of a triangle are 2, \sqrt{12} and \sqrt{19}.

Option (A).

If the triangle is a right triangle.

By Pythagoras theorem,

(Longest side)² = (Leg 1)² + (Leg 2)²

(\sqrt{19})^2=2^2+(\sqrt{12})^2

19 = 4 + 12

19 = 16

Not true.

Therefore, its not a right triangle.

Option (B).

If it is a triangle following conditions will be followed.

1). a + b > c

2). b + c > a

3). a + c > b

For the given sides of the triangle,

1). 2 + √12 > √19 [True]

2). 2 + √19 > √12 [True]

3). √12 + √19 > 2 [True]

Therefore, the given measures of the sides will form a triangle.

Option (C)

By Pythagorean inequality theorem,

If c² =  a² + b² → Right triangle

If c² > a² + b² → Obtuse triangle

If c² < a² + b² → Acute triangle

Since, (√19)² > 2² + (√12)² → 19 > 4 + 12

Therefore, the given triangle is an Obtuse triangle.

Option (D).

Not true. It's an obtuse triangle.    

3 0
3 years ago
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