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Novay_Z [31]
3 years ago
7

1. Suppose people ages 16-30 make up 15% of drivers on the road, 80% of drivers are aged 31-64, and 5% of drivers are aged 65+.

Furthermore, suppose drivers in each age range cause car accidents at the rates of 6%, 4%, and 9%, respectively. Given an accident occurred, what is the probability a driver aged 31-64 caused it? g
Mathematics
1 answer:
Yuliya22 [10]3 years ago
3 0

Answer:

0.8675

Step-by-step explanation:

Given that people ages 16-30 make up 15% of drivers on the road, 80% of drivers are aged 31-64, and 5% of drivers are aged 65+.

Furthermore, suppose drivers in each age range cause car accidents at the rates of 6%, 4%, and 9%, respectively.

age 16-30 31-64 >65  

Prob 0.15 0.8 0.05 1

Prob for accidents 0.06 0.09 0.04  

Product 0.009 0.072 0.002 0.083

Prob for 31-64 causing it/accident =\frac{0.072}{0.083} \\=0.8675

Using Bayes theorem we got answer as 0.8675

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Then divide 8 from both sides.

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