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3 years ago

I need help on these 4 questions. Please someone help me. Don’t put a link. Please help me.

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

Answer:

Median: b

Altitude: c

Angle bisector: a

Perpendicular bisector: d

Step-by-step explanation:

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What is the volume of the cylinder?

Umnica [9.8K]

Answer:

4712.39

Step-by-step explanation:

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3 years ago

A homeowner must reduce the use of his homes electricity . the home currently consumes 25.7 kwh (kilowatt hours) of electricity

tigry1 [53]

Given:
25.7 kwh of electricity per day.
must reduce 20%

25.7 kwh * 20% = 5.14 kwh * amount of electricity to be reduced.
25.7 kwh - 5.14 kwh = 20.56 kwh * net of reduced electricity

The homeowner will use 20.56 kwh after reduction of 20%.

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4 years ago

Which ratio would you use to find AC? Sine B) Cosine C) Tangent?

Levart [38]

Answer:

Step-by-step explanation: Sine

8 0

3 years ago

What is the volume of a cylinder if the radius is 8 and the height is 6

gizmo_the_mogwai [7]

Answer:

1205.76

Step-by-step explanation:

The formula for volume of a cylinder is : π(or 3.14)r²h

Plug in the variables and solve

(3.14)(8)²(6)

(3.14)64(6)

384(3.14)

1205.76

Hope this helps

6 0

3 years ago

Read 2 more answers

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

3 years ago

Read 2 more answers