Answer:
OBTUSE
Step-by-step explanation:
You would first have to figure this put via Pythagorean theroem. Basically do this (attachment)***C IS THE LARGEST NUMBER*** and know that c^2 < a^2 + b^2 (less than) = ACUTE, c^2 > a^2 + b^2 (greater than) = OBTUSE, and c^2 = a^2 + b^2 is RIGHT. If it is Right with all different numbers, it is SCALENE.
Answer:
the answer is D
Step-by-step explanation:
hope this helps
Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
Both of your answers are correct. In the first equation, if you were to substitute 3 for x, because you have to do exponents first, you have 3^2, which is 9, and 9*6 =54. If you were to substitute -3 for x again you would have to do the exponents first which would be -3^2 which is 9, and 9*6 = 54.
For the second question, if I substitute 0.75 for t, I get -9 + 18 + 7. This is equal to 16, and therefore the answer would be D. Hope this helps! :D. Let me know if you have questions about my explanation, and feel free to post more questions.
You can find 15 DVDs.
165 divided by 11 = 15
