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2 years ago

Find the midpoint of the line segment shown below.

Mathematics

1 answer:

a_sh-v [17]2 years ago

3 0

Answer:

(-3,-1.5)

Step-by-step explanation:

The two points are: (-2,1) & (-4,-4)

$x = \frac{ - 2 - 4}{2} = - 3 \\ \\ y = \frac{1 - 4}{2 } = - \frac{3}{2} = - 1.5$

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Mark made a scale drawing of a soccer field, using a scale of .5 cm=1m. The actual length of the field is 110 m. What is the len

VikaD [51]

Answer:

The length of the field on the drawing is <u>55 cm</u> that is option <u>D</u>.

Step-by-step explanation:

Given:

Mark made a scale drawing of a soccer field, using a scale of .5 cm=1 m.

The actual length of the field is 110 m.

Now, to find the length of the field on the drawing.

Let the length of the field on drawing be $x\ cm.$

As given,

Drawing of a soccer field, using a scale of 0.5 cm=1 m.

So, 0.5 cm is equivalent to 1 m.

Thus, $x\ cm$ is equivalent to 110 m.

Now, to get the length of the field on the drawing by using cross multiplication:

$\frac{0.5}{1} =\frac{x}{110}$

By cross multiplying we get:

$55=x$

$x=55\ cm$

Therefore, the length of the field on the drawing is 55 cm that is option D.

7 0

3 years ago

[Please help] I am very weak at functions, I just need yes's and no's! ;-;

egoroff_w [7]

Answer:

left to right

yes no no no yes yes yes yes yes yes yes no

Step-by-step explanation:

the x values can only have 1 y

Y's can have as many X's

5 0

2 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

What is the radius for a circle whose equation is +=367

salantis [7]

You are correct the answer is a:18

3 0

1 year ago

Read 2 more answers

Is 36 km greater than less than or equal to 36,000 m

guapka [62]

The answer is the same

6 0

3 years ago

Read 2 more answers