Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can
Shawn see to the horizon? Use the formula mc024-1.jpg, mc024-2.jpg with d being the distance they can see in miles and h being their eye-level height in feet.
We simply substitute the given values of h into the equation and compare the results.
For Wyatt where h = 120: d = </span>√(3(120)/2)<span> d = 13.42 miles
</span><span>For Shawn where h = 270: d = </span>√(3(270)/2)<span> d = 20.12 miles </span> Since the question asks for how much farther can Shawn see, we subtract the results:
The answer is D if the legs are 5 and 4 cm the equation to find the hypotenuse would be 5^2+4^2=c^c 5 squared is 25 and 4 squared is 16 that gives you 41, normally you would square root the 41 but it gives you a decimal number
