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Rainbow [258]
3 years ago
12

Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can

Shawn see to the horizon? Use the formula mc024-1.jpg, mc024-2.jpg with d being the distance they can see in miles and h being their eye-level height in feet.
Mathematics
1 answer:
brilliants [131]3 years ago
4 0
Using the formula given: d = <span>√(3h/2)

We simply substitute the given values of h into the equation and compare the results.

For Wyatt where h = 120:
d = </span>√(3(120)/2)<span>
d = 13.42 miles

</span><span>For Shawn where h = 270:
d = </span>√(3(270)/2)<span>
d = 20.12 miles
</span>
Since the question asks for how much farther can Shawn see, we subtract the results:

20.12 - 13.42 = 6.7

Therefore, Shawn can see 6.7 miles farther.
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