1/6+2/3+1/4
First find the highest common multiple of the denominators=12
Then multiply each term by the quotient of 12/denominator
So...it becomes 2/12+8/12+3/12
Add all the numerators and keep the denominator constant
It becomes (2+8+3)/12=13/12
=1 1/12
(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
Your answer is 3277 because a negative divided by a negitive makes it a positive.
