Answer:
Abundance of isotope 79Br=51% and abundance of 81Br=49%
Step-by-step explanation:
We are given that
Mass of 79Br=78.9183 u
Mass of 81Br=80.9163 u
Average atomic mass of bromine=79.90 u
We have to find the relative abundance of the two bromine isotopes.
Let x be the abundance of 79Br
Then , abundance of 81Br isotopes=1-x
Average atomic mass=Mass of isotope(abundance of isotope)+Mass of other isotope(abundance of other isotope)
Using the formula
Percentage of isotope with abundance 0.51=%
Abundance of other isotope=1-0.51=0.49
Percentage of other isotope with abundance 0.49=%
(-1.-2) and (3,6)
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Answer:
45
Step-by-step explanation:
1/3 of 90
= 1/3 * 90
= 90/3
= 30
Let the missing number be x.
2/3 of x
= 2/3 * x
= 2x/3
30 = 2x/3
Cross multiply,
2x = 30 * 3
2x = 90
x = 90/2
x = 45
Hence,
the missing number is 45.
Answer:
Number 1 is also 125 because it corresponds.
Step-by-step explanation:you see other line in the triangle right!if u see both are giving that line anywhere then you will know they corresponds! hope it hels!good night!