Answer:
4' x 2' x 1'
Step-by-step explanation:
Collins' cube has a volume of that is the length of any side, x, cubed: Vol = x^3. Since his box has 8^3, we can say that x = 2. <u>[2^3 = 8]</u>
Amil's box has one side that is 2x. That side would be 2*2 = 4 feet. His volume is also 8 ft^3. Amil's box also has a volume of 8 ft^3.
His box dimensions are therefore: (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.
(4)(X)(Y) = 8 ft^3
X*Y = 2
The only combination of whole numbers for which this this would work is 1 and 2.
Amil's box is 4' x 2' x 1' or 8 ft^3
Answer:
4
Step-by-step explanation:
Answer:
5x
Step-by-step explanation:
UwU
Answer:
Step-by-step explanation:
Given
Required
The phase
We have:
Rewrite as:
A cosine function is represented as:
Where:
Phase
By comparison:
Hence, the phase is:
Answer:
96 in²
Step-by-step explanation:
Lateral surface area
= 3 rectangles
(4×8) + (3×8) + (5×8)
32 + 24 + 40
96 in²
