All categories

3 years ago

20 POINTS JUST FOR YOU IF YOU GET IT RIGHT

Mathematics

1 answer:

marusya05 [52]3 years ago

3 0

Answer:

Because it is given that q ║ r and r ║ s, then q ║ s by the TRANSITIVE PROPERTY OF PARALLEL LINES. This means that 1   2 because the CORRESPONDING

ANGLES THM. Because b  q, m1 = 90. So, m2 =90. This means s  b, by definition of

perpendicular lines. It is given that a  s, so a ║ b BECAUSE IF TWO LINES ARE PERPENDICULAR

TO THE SAME LINES, THOSE LINES MUST BE PARALLEL

Step-by-step explanation

put in your own words

You might be interested in

Question 5

navik [9.2K]

Answer:

A. Similar using SAS; ∆ABC ~ ∆DFE

Step-by-step explanation:

m<B of ∆ABC = m<F of ∆DFE

AB corresponds to DF

AB/DF = 12/8 = 3/2

BC corresponds to FE

BC/FE = 24/16 = 3/2

Thus, the ratio of the corresponding sides of both triangles are the same. Therefore, both triangles has two sides that are proportional to each other, and also had an included corresponding angles that are congruent to each other.

By the SAS criterion, we can conclude that both triangles are similar to each other. That is, ∆ABC ~ ∆DFE

7 0

3 years ago

A parallelogram has symmetry with respect to the line that _____.

adelina 88 [10]

A parallelogram has symmetry wii respect to the line that C- Bisects it from opposite vertices.
All the others are never true for a parallelogram. You can try cutting out a parallelogram and folding it to see for yourself!
Hope this helps!!

4 0

3 years ago

Read 2 more answers

The equation __ describes the relationship

vivado [14]

Answer:

y= 1/3x

Step-by-step explanation:

points on the graph

(0,0), (3,1)

function as per above two points:

y= 1/3x

5 0

3 years ago

Points A, B, and C are collinear and A is between B and C.

olganol [36]

The answer is AB (45)

6 0

3 years ago

A gallery has 25 paintings in its permanent collection, with display space for 10 at one time. How many different collections ca

Anastaziya [24]

You need to know in how many ways you can choose 10 out of 25 items when order does not matter. This is a combination problem.

$_{n}C_{r} = \dfrac{n!}{(n - r)!r!}$

$_{25}C_{10} = \dfrac{25!}{(25 - 10)!10!}$

$_{25}C_{10} = \dfrac{25 \times 24 \times 23 \times 22 \times 21 \times 20 \times 19 \times 18 \times 17 \times 16 \times 15!}{15! \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}$

$_{25}C_{10} = \dfrac{25 \times 24 \times 23 \times 22 \times 21 
\times 20 \times 19 \times 18 \times 17 \times 16}{10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 
\times 2 \times 1}$

$_{25}C_{10} = \dfrac{23 \times 11 \times 20 \times 19 \times 2 \times 17}{1}$

$_{25}C_{10} = 23 \times 11 \times 20 \times 19 \times 2 \times 17$

$_{25}C_{10} = 3,268,760$

6 0

4 years ago

Read 2 more answers