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3 years ago

3(4x^2y^3 + 2x^3) – 4(9x^3y^2 – 6x^2y^3) How to solve pls?

Mathematics

1 answer:

babunello [35]3 years ago

4 0

Answer:

$3(4 {x}^{2} {y}^{3} + 2 {x}^{3}) - 4(9 {x}^{3} {y}^{2} - 6 {x}^{2} {y}^{3} ) \\ = (12 {x}^{2} {y}^{3} + 6 {x}^{3} ) - (36{x}^{3} {y}^{2} - 24{x}^{2} {y}^{3}) \\ = (12 {x}^{2} {y}^{3} + 6 {x}^{3} ) + ( - 36{x}^{3} {y}^{2} + 24{x}^{2} {y}^{3}) \\ = - 36{x}^{3} {y}^{2} + 36x^{2} {y}^{3} + 6 {x}^{3}$

I hope I helped you^_^

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QveST [7]

Answer:

<h2><em><u>m = 20</u></em></h2><h2><em><u>a = 48</u></em></h2><h2><em><u>These are the answers.</u></em></h2>

Step-by-step explanation:

1. m/-8 = -2.5

*-8 = *-8

m = -2.5*-8

m = 2.5*8

2. 7/8a = 42

*8 *8

7a = 336

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3 years ago

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tia_tia [17]

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Answer is C. 1:2

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3 years ago

Find an equation of the line perpendicular to the graph of 28x-7y=9 that passes through the point at (4,1)

kifflom [539]

If it is perpendicular to the line 14x-7y=4, then we know our line has the opposite and inverse slope of that line. Solving for y of the first line, we get y=2x-(4/7). All we care about is the coefficient of the x term, because that will give us our slope. The slope of the first line is 2, so the slope of out line is the opposite and inverse of that slope, which -(1/2).

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3 years ago

Find the slope trough (-22,3) and (11,-3)

velikii [3]

Answer:

The slope is $-\frac{2}{11}$

Step-by-step explanation:

Let $(x_1,y_1)=(-22,3)$ and $(x_2,y_2)=(11,-3)$

The slope is given by;

$m=\frac{y_2-y_1}{x_2-x_1}$

We plug in the values to get;

$m=\frac{-3-3}{11--22}$

Simplify;

$m=\frac{-6}{33}$

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4 years ago

Read 2 more answers

If the side lengths are 5 of a square, what is the area ?

iogann1982 [59]

Since each of the sides of a square must all be the same length, the width and length of the square are both 5. The formula for the area of a square is
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3 years ago