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Novay_Z [31]
4 years ago
14

How do you find 2,13 and 5,22 in slope intercept form

Mathematics
2 answers:
Kazeer [188]4 years ago
5 0

Hello : let

 A(5,22)    B(2,13)


the slope is :   (YB - YA)/(XB -XA)


(13-22)/(2-5)  = -9/-3


an equation is : y=ax+b     a is a slope


y = 3x +b


 


the line through point A (5,22) :

 22 = 3(5)+b

b = 7


the equation is : y =3x+7



spayn [35]4 years ago
5 0
Y = mx + b

Find m first

m = 22 - 13 / 5-2
m = 9/3
m = 3

find b

Y = 3x + b

Substitute for x and y coordinates

13 = 3(2) + b

13 = 6 + b

7 = b

Y = 3x + b
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The conclusion about the functions is they have the same y-intercept.

<h3>How to make conclusion about the functions?</h3>

The complete question is added as an attachment

The function is given as:

f(x) = (x + 4)^2

From the attached graph, the graph has a y-intercept at:

y = 16

This can be represented as:

(0, 16)

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f(0) = (0 + 4)^2

Evaluate

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This means that the y-intercept of f(x) = (x + 4)^2 is (0, 16)

So, the functions have the same y-intercept

Hence, the conclusion about the functions is they have the same y-intercept.

Read more about y-intercept at

brainly.com/question/25722412

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