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rjkz [21]
3 years ago
10

A grocery store has 48 cartons of eggs. If there are 12 eggs in each carton.how many eggs are there?

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0
Hi there, all we do is divide 48 by 12. 48÷12=4.
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A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

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3 years ago
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Answer:

Step-by-step explanation:

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3 years ago
Simplify the expression- 3 - 5/6 / 5/2
spin [16.1K]

Answer:

10/3

Step-by-step explanation:

-3-5/6/5/2=-10/3

decimal 0.33333 reaccuring

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3 years ago
Diabetes is a disease that affects millions of Americans. In fact, about 25,585,000 U.S. adults had diabetes in 2010. At that ti
denis-greek [22]

Answer:

8.28%

Step-by-step explanation:

According to the U.S. Census Bureau, the legal official department in charge of the National Census every ten years, the population of the U.S.A in 2010 was<em> 308,745,538 inhabitants.</em>

If about 25,585,000 had diabetes, then <em>cross multiplying</em>

308,745,538-------100%

25,585,000---------x%

and

\frac{308,745,538}{25,585,000}=\frac{100}{x}

and so, about

x=\frac{25,585,000*100}{308,745,538}=8.28 \%

Americans had diabetes in 2010.

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3 years ago
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Look at the picture attached

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