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3 years ago

6

hi whoever is reading this, please consider helping me. click on this. I know the answer is 19 because a is 18 and b is 1 but id

k how to solve it algebraically.

1 answer:

babymother [125]3 years ago

5 0

Answer:

A= 108

Step-by-step explanation:

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<u>Algebra I</u>

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<u>Step 2: Break Function</u>

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Answer:

$1) {n}^{2} - 81 \\ (n - 9)(n + 9)$

$2) \: \: {a}^{2} - 121 \\ (a - 11)(a + 11)$

$3) \: \: {n}^{2} - 16 \\ (n - 4)(n + 4)$

$4) \: \: 9 {x}^{2} - 144 \\ {3}^{2} {x}^{2} - {12}^{2} \\ (3x - 12)(3x + 12)$

$5) \: 2 {x}^{2} - 9 \\ (2x - 3)(x + 3)$

$6) \: \: 4 {w}^{2} - 9 \\ {2}^{2} {w}^{2} - {3}^{2} \\ (2w + 3)(2w - 3)$

$7) \: \: 4 {n}^{2} - 1 \\ {2}^{2} {n}^{2} - {1}^{2} \\ (2n + 1)(2n - 1)$

$8) \: \: 1 - 16 {x}^{2} \\ {1}^{2} - {4}^{2} {x}^{2} \\ (1 - 4x)(1 + 4x)$

$9) \: \: {x}^{2} - {y}^{2} \\ (x - y)(x + y)$

$10) \: \: 9 - {c}^{2} \\ {3}^{2} - {c}^{2} \\ (3 - c)(3 + c)$

$11) \: \: {n}^{2} - 25 \\ {n}^{2} - {5}^{2} \\ (n + 5)(n - 5)$

$13)49 - 4 {a}^{2} \\ {7}^{2} - {2}^{2} {a}^{2} \\ (7 - 2a)(7 + 2a)$

$14) {a}^{2} {b}^{2} - {c}^{4} \\ (ab - {c}^{2} )(ab + {c}^{2} )$

$15) \: \: 4 {x}^{2} {y}^{2} - 9 {z}^{2} \\ {2}^{2} {x}^{2} {y}^{2} - {3}^{2} {z}^{2} \\ (2xy - 3z)(2xy + 3z)$

hope this helps

sorry, I don't know how solve the 12th one.

thanks.

7 0

3 years ago