Answer:
x=0.9
Step-by-step explanation:
(ask me if u want it)
Answer:
<h2>12) There are 534 students who do not lunch in school.</h2>
Step-by-step explanation:
<h3>12. </h3><h3>Simple solution: </h3><h3>890 ÷ 5 = 178 </h3><h3>Therefore: 1/5 = 178 </h3><h3 /><h3>•To find the 2/5 of the students, we have to multiply 178 by 2</h3><h3>178 × 2 = 356</h3><h3>Therefore, 356 students stay to have lunch.</h3><h3 /><h3>•To find the remaining students who do not lunch in school, we have to subtract 356 to 890.</h3><h3>890 - 356 = 534</h3><h3>Therefore, there are 534 students who do not lunch in school.</h3><h3 /><h3 />
Answer:
a) x value is -2, min is -3(if thats y)
b) x value is 3, max is 21(if thats y)
Step-by-step explanation:
yes you do quadratic formula and such :)
Answer:
1 x=-2.5 y = -5.5
2. x=5 y=1
Step-by-step explanation:
1) What is the solution of the given system?
5x-y=-7
3x-y=-2
Multiply the second equation by -1
-1*(3x-y)=-1(-2)
-3x +y = 2
Now add the first equation to the modified second equation
5x-y=-7
-3x +y = 2
------------------
2x = -5
Divide each side by 2
2x/2 = -5/2
x = -2.5
Now we need to find y
-3x+y =2
-3(-2.5) +y =2
7.5 +y =2
Subtract 7.5 from each side
7.5 -7.5 +y =2-7.5
y = -5.5
2) what is the solution of the given system?
5x+7y=32
8x+6y=46
Divide the second equation by 2
8x/2+6y/2=46/2
4x+3y =23
Multiply the first equation by 4
4 (5x+7y)=32*4
20x+28y = 128
Now multiply the modified 2nd equation by -5
-5(4x+3y )=-5(23
)
-20x -15y = -115
Lets add the new equations together to eliminate x
20x+28y = 128
-20x -15y = -115
---------------------
13y = 13
Divide each side by 13
13y/13 =13/13
y=1
Now substitute back in to find x
5x+7y=32
5x +7(1) =32
5x +7 =32
Subtract 7 from each side
5x+7-7 =32-7
5x =25
Divide by 5
5x/5 =25/5
x=5
91$ per day you divid 455$ by the 5 days and get 91$
