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Nana76 [90]
4 years ago
9

Help!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
pav-90 [236]4 years ago
5 0

Answer: When distance increases, gravity decreases.

When distance decreases, gravity increases.

This means they have an inversely proportional relationship.

Step-by-step explanation:

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Which of the following represents the area of a rectangle whose length is x + 1 and whose width is x + 11?
shtirl [24]
You would foil (x+1)(x+11)

x^2 + 12x + 11
8 0
4 years ago
If 0.00005893 is expressed in the form 5.893 × 10n, what is the value of n ?
yan [13]
In the scientific value of 5.893 x 10n. The standard value is 0.00005893 what is n? To better illustrate this phenomenon, we can explain it further under the rules of scientific notation.
For example. <span><span>
1. </span><span> 3 x 10^3 = 3 x 100 = 300</span></span>
<span><span>2. </span><span> 3 x 10^-3 = 3 x 0.001 = 0.003</span></span>

Solution:
0.00005893 = 5.893 x 0.00001 = 5.893 x 10^-5  
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Solve the division problem. Round answer to the nearest hundredth.<br> 52.063/9.2
Colt1911 [192]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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If B=16 degrees 45' and c=13 find a
Vinvika [58]
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Fill in the blanks. Suppose the probability at a light bulb factory of a bulb being defective is 0.11. If a shipment of 133 bulb
anastassius [24]

Answer:

The number of defective bulbs in the shipment should be around 15, give or take 4.

Step-by-step explanation:

For each bulb, there are only two possible outcomes. Either it is defective, or it is not. The probability of a bulb being defective is independent of any other bulb. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Suppose the probability at a light bulb factory of a bulb being defective is 0.11

This means that p = 0.11

Shipment of 133 bulbs:

This means that n = 133

Mean and standard deviation:

E(X) = np = 133*0.11 = 14.63

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{133*0.11*0.89} = 3.61

Rounding to the nearest integers:

The number of defective bulbs in the shipment should be around 15, give or take 4.

8 0
3 years ago
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