All categories

3 years ago

PLEASE HELP I’M SO CONFUSED

Mathematics

1 answer:

bekas [8.4K]3 years ago

5 0

Answer:

a. $45 an hour

b. 5.25 hours

Step-by-step explanation:

a. The plumber charges $75 per job, so it is irrelevant to the number of hours they work. 45(h) is $45 multiplied by the number of hours they work.

First, plug the numbers into the equation, the cost being C(h):

311.25 = 45(h) + 75

Next, subtract $75 as it is a set price that is always payed:

236.25 = 45(h)

Then, divide both sides by 45 to find how many hours were worked:

h = 5.25

Hours = $5.25

You might be interested in

Peyton has collected 120 aluminum cans for recycling. If 20 cans will fit in each blue plastic bag, how many bags will she need

gogolik [260]

Hi Renee!

--------------------------------------------

We Know:

120 aluminum cans.

20 cans fit in each blue bag.

--------------------------------------------

Solution:

120 / 20 = 6

--------------------------------------------

Answer:

She will need 6 bags to carry all the aluminum cans.

--------------------------------------------

Hope This Helps :)

6 0

2 years ago

Perpendicular line equation to y=3/5x+1

natulia [17]

Answer:

Find the negative reciprocal of the gradient, so 3 / 5 will switch its denominator with its numerator, and it will have the opposite sign.

So 3/5 will be - 5/3

Answer:

y = - 5 / 3x + 2

3 0

3 years ago

Make an equivalent fraction with the denominator 10,100, or 1000

evablogger [386]

10000/10,000. :) :) dh

5 0

2 years ago

A teacher was interested in finding out whether a special study program would increase the scores of students on a national exam

bija089 [108]

Answer:

Check the explanation

Step-by-step explanation:

Going by the first attached image below we reject H_o against H_1 if obs. $T > t_{\alpha /2;n-1}$

here obs.T=1.879

$\therefore obs.T \ngtr 2.447=t_{0.025;6}$

we accept $H_o:\mu _{1}=\mu_{2}$ at 5% level of significance.

i.e there is no sufficient evidence to indicate that the special study program is more effective at 5% level of significance.

this problem is simillar to the previous one except the alternative hypothesis.

Let X_i's denote the bonuses given by female managers and Y_i's denote the bonuses given by male managers.

we assume that $X_i \sim N(\mu _{1},\sigma _{1}^{2}) Y_i \sim N(\mu _{2},\sigma _{2}^{2})$ independently

We want to test $H_0:\mu_{1}=\mu_{2} vs H_1:\mu_{1}\neq \mu_{2}$

define $D_i=X_i-Y_i , i=1(1)8$

now $D_i\sim N(\mu _{1}-\mu _{2}=\mu _{D},\sigma _{1}^{2}+\sigma _{2}^{2}=\sigma _{D}^{2}) , i=1(1)8$

the hypothesis becomes

$H_0:\mu_{D}=0 vs H_1:\mu_{D}\neq 0$

in the third attached image, we use the same test statistic as before

i.e at 5% level of significance there is not enough evidence to indicate a difference in average bonuses .

3 0

2 years ago

Help pls

stepladder [879]

Answer:

below

Step-by-step explanation:

therefore 2250 loaves where'nt sold

5 0

2 years ago

Read 2 more answers