The point of intersection of the two lines is at (1,-1)
<h3>System of equation</h3>
The given system of expression is shown below
x - 2y = 3
5x + 3y = 2
The solution to the system of equation is the point of intersection
From equation 1
x = 3 + 2y
Substitute into 2
5(3+2y) + 3y = 2
15 +10y + 3y = 2
13y = -13
y = -1
Substitute y = -1 into 3
x = 3 + 2y
x = 3+(-2)
x = 1
Hence the point of intersection of the two lines is at (1,-1)
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b - 10 = 7
Take 10 to the other side.
b = 17
Multiply by 4 to isolate b
b × 4 = 17 × 4
4 and 4 cancels out
b = 68
4/5x-8=3
move -8 to the other side and add
4/5x=3+8
4/5x=11
move 5x to the other side and multiply
4=5x*11
4=55x
4/55=x
The answer is 1.
Im too lazy to show the work, but heres how I checked
-7(1 + 2) = -14 - 7
-7 + (-14) = -14 - 7
-21 = -21
