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Masja [62]
3 years ago
11

A rhombus has coordinates A(-6, 3), B(-4, 4), C(-2, 3), D(-4, 2). What are the coordinates of rhombus A'B'C'D' AFTER A 90° COUNT

ERCLOCKWISE ROTATION ABOUT THE ORIGIN FOLLOWED BY A TRANSLATION 3 UNITS TO THE LEFT AND 2 UNITS DOWN ?
Mathematics
1 answer:
Effectus [21]3 years ago
5 0

Answer:

See below.

Step-by-step explanation:

Firstly the counterclockwise  rotation is (x, y)  ---> (-y, x), so A(-6, 3) moves to (-3, -6).

Then the translation (-3, -6) ---> ( -3-3), -6) = (-6, -6)   (3 units to the left).

Finally the second translation  moves (-6, -6) to (-6, -6-2) = (-6, -8)  = A'  ( 2 units down).

The coordinates of B', C' and D' are calculated in exactly the same way.

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3 years ago
Find the next term is in the explicit and recursive rule for the in term of the sequence. NO LINKS!!!
BARSIC [14]

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Answer:

  5) 729, an=3^n, a[1]=3; a[n]=3·a[n-1]

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Step-by-step explanation:

The next term of a geometric sequence is the last term multiplied by the common ratio. (This is the basis of the recursive formula.)

The Explicit Rule is ...

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The Recursive Rule is ...

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5. First term is a₁ = 3; common ratio is r = 9/3 = 3.

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Recursive rule: a[1] = 3; a[n] = 3·a[n-1]

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6. First term is a₁ = 7; common ratio is r = 28/7 = 4.

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7 0
3 years ago
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Step-by-step explanation:

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Hi there

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