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3 years ago

Earn 100 points for this question and a brainiest

Mathematics

2 answers:

padilas [110]3 years ago

6 0

Answer:

the answer is C

Step-by-step explanation:

$\frac{7}{7} - \frac{4}{7} + \frac{2}{7}$

malfutka [58]3 years ago

5 0

Step-by-step explanation:

Step 1 :-

> 7/7 - 4/7

> 7-4/7

> 3/7

Step 2 :-

> 3/7 + 2/7

> 3 + 2/7

> 5/7

Option C is correct 

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3 years ago

What is the derivative of ln(lnx^3)

chubhunter [2.5K]

the derivative of ln(lnx^3) is $\frac{1}{x(lnx)}$ .

Step-by-step explanation:

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , $ln(lnx^3)$ , Let's differentiate it w.r.t x :

⇒ $\frac{d(ln(lnx^3))}{dx}$

Let $lnx^3 = u$

⇒ $\frac{d(ln(u))}{dx}$

⇒ $\frac{1}{u} (\frac{d(u)}{dx} )$

⇒ $\frac{1}{u} (\frac{d(ln(x^3))}{dx} )$

Let $x^3=v$

⇒ $\frac{1}{u} (\frac{d(ln(v))}{dx} )$

⇒ $\frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )$

⇒ $\frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )$

⇒ $3x^2(\frac{1}{u})(\frac{1}{v} )$

Putting value of u & v we get:

⇒ $3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )$

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⇒ $\frac{3}{3x(lnx)}$

⇒ $\frac{1}{x(lnx)}$

Therefore , the derivative of ln(lnx^3) is $\frac{1}{x(lnx)}$ .

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3 years ago

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Verdich [7]

(-1,-3)

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