Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
Answer:
The answer is 104,453.
Step-by-step explanation:
Multiply 1,023 and 102 first because you always have to do your problems left to right in math. Your equation should now look like 104,346 + 112 - 5. Calculate the sum of the positive numbers by adding 104, 346 + 112. Your equation should now be 104,458 - 5. Then lastly, you subtract the numbers 104,458 and 5, and you should get 104, 453 as your answer.
