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aniked [119]
3 years ago
14

Circle towns limit form a perfectly circular shape that has a population of 20000 in the population density of 480 people per sq

uare kilometer what is circle X radius
Mathematics
1 answer:
Alex3 years ago
6 0

Answer:

D =\frac{P}{\pi X^2}

And solving for the radius we got:

X = \sqrt{\frac{P}{\pi D}}

And replacing the data given we got:

X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km

And this value converted to meters is X = 87.40 m

Step-by-step explanation:

For this case we know the population size P = 20000 and we also know the population density D = 480 \frac{people}{km^2}

We can assume that the area is a circle. We also know that the formula for the population density is given by:

D= \frac{P}{A}

Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:

A = \pi X^2

With X the radius of the circle

And then the populationd density become:

D =\frac{P}{\pi X^2}

And solving for the radius we got:

X = \sqrt{\frac{P}{\pi D}}

And replacing the data given we got:

X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km

And this value converted to meters is X = 87.40 m

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pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

<u>Let radius of the small sphere = </u>x<u />

<u>As the radius of the large sphere is double the radius of the small sphere:</u>

Then, radius of the large sphere = 2x

To find that how many times is the volume of the large sphere than the small sphere, we will <em><u>divide the volume of large sphere by  volume of small sphere:-</u></em>

For smaller sphere: Radius = x

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For larger sphere: Radius = 2x

Volume \ of \ sphere = \frac{4}{3} \pi r^{3}

                             =\frac{4}{3} \pi (2x)^{3}

Now, we will divide volume of the larger by the smaller one:

=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\  \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\  \times\frac{1}{x^{3} }

\frac{4}{3}\pi\   is \ canceled\  by\  \frac{3}{4\pi } \ and\ also\ x^{3} is\ canceled\ by \ \frac{1}{x^{3} }

<u>Now, we have</u>

= \frac{8}{1}

Therefore, the volume of the large sphere is 8 times larger than the smaller sphere.

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Step-by-step explanation:

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