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2 years ago

What is the perimeter of the figure?

Mathematics

2 answers:

Monica [59]2 years ago

7 0

Hey there,

So when finding the perimeter, we do addition.

So . . .

20 + 12 + 18 + 7+ 13+6

Your correct answer would be 76

Hope this helps.
~Jurgen

larisa86 [58]2 years ago

6 0

Hey there!

To get this perimeter, we need to have all the side lengths. In this picture, all side lengths but 2 is given. Thus, we have to find the two missing side lengths.

$20-7=13$
$18-12=6$

Thus, the two missing side lengths are 13 and 6.
Now, let's add all the side lengths.

$20+12+18+7+13+6$
$=\boxed{76}$

The perimeter is 76 inches, which is answer choice D.
Hope this helps! :)<span />

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3 years ago

Find the volume and area for the objects shown and answer Question

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Step-by-step explanation:

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$\\\text{we need to calculate the height of two different side walls}\ h_1\ \text{and}\ h_2\\\text{use the Pythagorean theorem:}\\\\h_1^2=\left(\dfrac{l}{2}\right)^2+h^2\to h_1=\sqrt{\left(\dfrac{l}{2}\right)^2+h^2}=\sqrt{\dfrac{l^2}{4}+h^2}=\sqrt{\dfrac{l^2}{4}+\dfrac{4h^2}{4}}\\\\h_1=\sqrt{\dfrac{l^2+4h^2}{4}}=\dfrac{\sqrt{l^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{l^2+4h^2}}{2}$

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$SA=lw+2\cdot\dfrac{lh_1}{2}+2\cdot\dfrac{wh_2}{2}\\\\SA=lw+2\!\!\!\!\diagup\cdot\dfrac{l\cdot\frac{\sqrt{l^2+4h^2}}{2}}{2\!\!\!\!\diagup}+2\!\!\!\!\diagup\cdot\dfrac{w\cdot\frac{\sqrt{w^2+4h^2}}{2}}{2\!\!\!\!\diagup}\\\\SA=lw+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw}{2}+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw+l\sqrt{l^2+4h^2}+w\sqrt{w^2+4h^2}}{2}$

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2 years ago

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bixtya [17]

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hope this helps!

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3 years ago