The product of three and a square number is twice the sum of the number and four

1 answer:

5 0

Write an equation, calling the number x:

3x=2(x+4)

3x=2x+8

x=8

However, 8 is not a perfect square, which was required in the problem, so there are no solutions.

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Determine whether the ordered pair (1, 1) is a solution of the inequality. y ≤ -3x+1

solong [7]

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Answer: $\textsf{(1, 1) is NOT a solution of the inequality}$

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Given: $y \le-3x + 1$

Find: $\textsf{Determine if (1, 1) is a solution of the inequality}$

Solution: In order to determine if (1, 1) is a solution we need to plug in 1 for the x values and 1 for the y values and see if the equation evaluated to true.

Plug in the values

$y \le-3x + 1$

$1 \le-3(1) + 1$

Simplify

$1 \le-3 + 1$

$1 \le-2$

As we can see the expression states that 1 is less than or equal to -2 which is false therefore (1, 1) is NOT a solution of the inequality.

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