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creativ13 [48]
3 years ago
10

A "b" value of less than 1 produces a graph with exponential decay

Mathematics
1 answer:
Andru [333]3 years ago
5 0
<span>If this statement is a True or False question.

Then, TRUE. A "b" value of less than 1 produces a graph with exponential decay.

We consider this formula: y = a*b^x or f(x) =a*b^x

a is the initial value, b is the rate, x is the exponent. 

If b has a value of less than 1, as the exponent increases the resulting value of y decreases.

f(x) = 20(0.90)^x

f(1) = 200(0.90)</span>¹ = 180
f(2) = 200(0.90)² = 162
f(3) = 200(0.90)³ = 145.80
f(4) = 200(0.90)⁴ = 131.22
f(5) = 200(0.90)⁵ = 118.10

Exponential decay is the decrease in a quantity. As you can see in the given example the value of f(x) decreases as the value of x increases because the value of b is less than 1.
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2 years ago
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Can someone finish the whole thing ??
Romashka-Z-Leto [24]
<h3>Answer:    y = (3/2)x + 0</h3>

This is the same as  y = (3/2)x

=============================================================

Work Shown:

Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)

m = (y2 - y1)/(x2 - x1)

m = (3 - (-3))/(2 - (-2))

m = (3 + 3)/(2 + 2)

m = 6/4

m = 3/2

The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.

----------

Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.

y - y1 = m(x - x1)

y - (-3) = (3/2)(x - (-2))

y + 3 = (3/2)(x + 2)

y + 3 = (3/2)x + (3/2)(2)

y + 3 = (3/2)*x + 3

y + 3 - 3 = (3/2)*x + 3 - 3

y = (3/2)x + 0

The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.

3 0
3 years ago
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