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3 years ago

Is 6.35 greater than 6.7

Mathematics

2 answers:

Alik [6]3 years ago

6 0

Answer:

Step-by-step explanation:

always look at the number after point

Greeley [361]3 years ago

6 0

Answer:

Step-by-step explanation:

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need help with this someone please help

qwelly [4]

Answer: B

Step-by-step explanation:

7 0

3 years ago

40% of x is 35 Write an equation that shows the relationship of 40%, X, and 35.

zhenek [66]

Answer:

87.5

Step-by-step explanation:

7 0

3 years ago

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the

Nookie1986 [14]

X the first account interest = x/100*2 = 2x/100
(x + 800)/100 * 4 =( 4x + 3200)/100
2x/100 + (4x + 3200)/100 = 92
2x + 4x + 3200 = 9200
6x = 6000
x = 1000
C is the answer

3 0

4 years ago

Read 2 more answers

The measure of each exterior angle of a regular polygon is 15 degrees. The length of each side is 4 inches. What is the length o

shutvik [7]

The length of the apothem is equal to 7.46in

Data;

Angle = 15 degree
s = 4 inches
length of apothem

<h3>Length of an Apothem</h3>

This can be calculated using the formula

$A = \frac{s}{2*tan(\frac{180}{n}) } \\A = \frac{4}{2*tan(\frac{180}{12}) } \\A = 7.46in$

The length of the apothem is equal to 7.46in

Learn more on length of an apothem here;

brainly.com/question/3654884

4 0

3 years ago

If sinx+sin^2x=1 then what is the value of cos^12x+3cos^10x+3cos^8x+cos^6x

mr_godi [17]

$\sin x+\sin^2x=1\implies\sin x=1-\sin^2x=\cos^2x$

$\cos^{12}x+3\cos^{10}x+3\cos^8x+\cos^6x=\sin^6x+3\sin^5x+3\sin^4x+\sin^3x$
$=\sin^3x(\sin^3x+3\sin^2x+3\sin x+1)$
$=\sin^3x(\sin x+1)^3$

Let $y=\sin x$ . Then

$\sin^2x+\sin x-1=0\iff y^2+y-1=0\implies y=-\varphi,y=\varphi-1$

where $\varphi=\dfrac{1+\sqrt5}2\approx1.61803$ is the golden ratio.

$\begin{cases}y=-\varphi\\y=\varphi-1\end{cases}\implies\begin{cases}\sin x=-\varphi\\\sin x=\varphi-1\end{cases}$

Since $|\sin x|\le1$ for all real $x$ , we can omit the first equation, leaving us with

$\sin x=\varphi-1\approx0.61803$

$\cos^{12}x+3\cos^{10}x+3\cos^8x+\cos^6x=\sin^3x(\sin x+1)^3$
$=(\varphi-1)^3\varphi^3$
$=1$

where the last equality follows from the fact that $\varphi=1+\dfrac1\varphi$ .

7 0

3 years ago