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murzikaleks [220]
3 years ago
12

Please help me I need to get this done!!!

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

y=-3x+4

Step-by-step explanation:

The question is asking for the equation in slope-intercept form. This is y=mx+b where m is the slope and b is the y-intercept.

The slope can be found by counting the units in between two points on the graph. Remember that slope is rise over run or y/x. Two points on the graph are (2,-2) and (1,1). The y is increasing by 3 while x is decreasing by 1. This means the slope is -3.

The y-intercept is where the line intersects with the y-axis. In this case, that point is (0,4). Therefore, b=4.

The final answer is y=-3x+4.

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Can someone helpp pleaseee, ill paypal you 15$
svetoff [14.1K]

Step-by-step explanation:

The angles on the same side of the parallel lines and the transversal are called corresponding angles.

Corresponding angles are congruent

So 11x+1 = 10x+10

x = 10-1 = 9

11*9+1 = 100

So both are 100 degrees

7 0
2 years ago
Jasmine Is organizing a carnival with games Booths she needs three volunteers per booth there are 16 booth if 62 people signed u
mr_godi [17]

14 volunteers will not be able to help.

Step-by-step explanation:

According to given statement;

One booth requires 3 Volunteers.

No. of booths = 16

Given number of volunteers = 62

We will multiply total number of booths with 3 to find the number of volunteers required.

Volunteers required = No. of booths x 3

Volunteers required = 16*3\\

Volunteers required = 48

Subtract the required volunteers from total volunteers;

62-48=14

14 volunteers will not be able to help.

Keywords: Subtraction, Multiplication.

Learn more about subtraction at:

  • brainly.com/question/1900154
  • brainly.com/question/1929680

#LearnwithBrainly

4 0
3 years ago
Which graph shows the solution set of the compound inequality or 1.5x-1 > 6.5 or 7x+3 < -25 ?
Dmitry [639]
1.
<span>1.5x-1 > 6.5 
1.5x>1+6.5
</span>1.5x>7.5, divide by 1.5

x>5, is represented by the region to the right of the vertical line x=5 

2. 

<span>7x+3 < -25
7x<-25-3
7x<-28, divide by 4:

x<-4

</span>x<-4, is represented by the region to the left of the vertical line x=-4

Answer: check the picture

6 0
3 years ago
Read 2 more answers
What is the value of the letter n?
sleet_krkn [62]

Answer:

The value of n depends on the questin. N would be a variable in an equation.

Step-by-step explanation:

For example. 2*n=6

n is the variable in the equation. Therefore, the value of n is 3. Because 2*3=6.

8 0
3 years ago
Lim n→∞[(n + n² + n³ + .... nⁿ)/(1ⁿ + 2ⁿ + 3ⁿ +....nⁿ)]​
Schach [20]

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given expression is

\rm :\longmapsto\:\displaystyle\lim_{n \to \infty}  \frac{n +  {n}^{2}  +  {n}^{3}  +  -  -  +  {n}^{n} }{ {1}^{n} +  {2}^{n} +  {3}^{n}  +  -  -  +  {n}^{n} }

To, evaluate this limit, let we simplify numerator and denominator individually.

So, Consider Numerator

\rm :\longmapsto\:n +  {n}^{2} +  {n}^{3}  +  -  -  -  +  {n}^{n}

Clearly, if forms a Geometric progression with first term n and common ratio n respectively.

So, using Sum of n terms of GP, we get

\rm \:  =  \: \dfrac{n( {n}^{n}  - 1)}{n - 1}

\rm \:  =  \: \dfrac{ {n}^{n}  - 1}{1 -  \dfrac{1}{n} }

Now, Consider Denominator, we have

\rm :\longmapsto\: {1}^{n} +  {2}^{n} +  {3}^{n}  +  -  -  -  +  {n}^{n}

can be rewritten as

\rm :\longmapsto\: {1}^{n} +  {2}^{n} +  {3}^{n}  +  -  -  -  +  {(n - 1)}^{n} +   {n}^{n}

\rm \:  =  \:  {n}^{n}\bigg[1 +\bigg[{\dfrac{n - 1}{n}\bigg]}^{n} + \bigg[{\dfrac{n - 2}{n}\bigg]}^{n} +  -  -  -  + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]

\rm \:  =  \:  {n}^{n}\bigg[1 +\bigg[1 - {\dfrac{1}{n}\bigg]}^{n} + \bigg[1 - {\dfrac{2}{n}\bigg]}^{n} +  -  -  -  + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]

Now, Consider

\rm :\longmapsto\:\displaystyle\lim_{n \to \infty}  \frac{n +  {n}^{2}  +  {n}^{3}  +  -  -  +  {n}^{n} }{ {1}^{n} +  {2}^{n} +  {3}^{n}  +  -  -  +  {n}^{n} }

So, on substituting the values evaluated above, we get

\rm \:  =  \: \displaystyle\lim_{n \to \infty}  \frac{\dfrac{ {n}^{n}  - 1}{1 -  \dfrac{1}{n} }}{{n}^{n}\bigg[1 +\bigg[1 - {\dfrac{1}{n}\bigg]}^{n} + \bigg[1 - {\dfrac{2}{n}\bigg]}^{n} +  -  -  -  + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]}

\rm \:  =  \: \displaystyle\lim_{n \to \infty}  \frac{ {n}^{n}  - 1}{{n}^{n}\bigg[1 +\bigg[1 - {\dfrac{1}{n}\bigg]}^{n} + \bigg[1 - {\dfrac{2}{n}\bigg]}^{n} +  -  -  -  + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]}

\rm \:  =  \: \displaystyle\lim_{n \to \infty}  \frac{ {n}^{n}\bigg[1 - \dfrac{1}{ {n}^{n} } \bigg]}{{n}^{n}\bigg[1 +\bigg[1 - {\dfrac{1}{n}\bigg]}^{n} + \bigg[1 - {\dfrac{2}{n}\bigg]}^{n} +  -  -  -  + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]}

\rm \:  =  \: \displaystyle\lim_{n \to \infty}  \frac{\bigg[1 - \dfrac{1}{ {n}^{n} } \bigg]}{\bigg[1 +\bigg[1 - {\dfrac{1}{n}\bigg]}^{n} + \bigg[1 - {\dfrac{2}{n}\bigg]}^{n} +  -  -  -  + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]}

\rm \:  =  \: \displaystyle\lim_{n \to \infty}  \frac{1}{\bigg[1 +\bigg[1 - {\dfrac{1}{n}\bigg]}^{n} + \bigg[1 - {\dfrac{2}{n}\bigg]}^{n} +  -  -  -  + \bigg[{\dfrac{1}{n}\bigg]}^{n} \bigg]}

Now, we know that,

\red{\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to \infty} \bigg[1 + \dfrac{k}{x} \bigg]^{x}  =  {e}^{k}}}}

So, using this, we get

\rm \:  =  \: \dfrac{1}{1 +  {e}^{ - 1}  + {e}^{ - 2} +  -  -  -  -  \infty }

Now, in denominator, its an infinite GP series with common ratio 1/e ( < 1 ) and first term 1, so using sum to infinite GP series, we have

\rm \:  =  \: \dfrac{1}{\dfrac{1}{1 - \dfrac{1}{e} } }

\rm \:  =  \: \dfrac{1}{\dfrac{1}{ \dfrac{e - 1}{e} } }

\rm \:  =  \: \dfrac{1}{\dfrac{e}{e - 1} }

\rm \:  =  \: \dfrac{e - 1}{e}

\rm \:  =  \: 1 - \dfrac{1}{e}

Hence,

\boxed{\tt{ \displaystyle\lim_{n \to \infty}  \frac{n +  {n}^{2}  +  {n}^{3}  +  -  -  +  {n}^{n} }{ {1}^{n} +  {2}^{n} +  {3}^{n}  +  -  -  +  {n}^{n} } =  \frac{e - 1}{e} = 1 -  \frac{1}{e}}}

3 0
2 years ago
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