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4 years ago

Add. 3/2x+4 + 2x/3x+6 and it'd be great if you show you work, thank you! ♡

Mathematics

1 answer:

Vikki [24]4 years ago

7 0

Answer:

2 1/6x +10

Step-by-step explanation:

All you need to do is combine like terms.

3/2x+4+2/3x+6

3/2x+10+2/3x

3/2x + 2/3x= 2 1/6x

2 1/6x+10

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Cancel the common factor of the numerator and the denominator and write specified expression

lisabon 2012 [21]

Step-by-step explanation:

Hello,

I hope you mean to cancel the common factor that exists in numerator and denominator,right.

so, Let's look for the common factor, 

here, the expression is, 

=4(x-2)/ (x+5)(x-2)

so, here we find the common factor is (x-2)

now, we have to cancel it. And after cancelling we get,

=4/(x+5)

Note:{ we cancel the common factor if the common factors are in multiply form.}

Hope it helps 

3 0

3 years ago

The Cutty Sark is a famous clipper ship (look it up)! A Cutty Sark model kit advertises a scale ratio of 1: 78, a length of 45 i

lukranit [14]

Answer: If the ratio is 1:78, a) the Cutty Sark is 3510 inches long or 292.5 ft; b) the Cutty Sark is 2028 inches tall or 169 ft according to this model

Step-by-step explanation: The ratio indicates that for every inch of the model, it corresponds to 78 inches of the actual size. If the length is 45 inches for the model, it would be an equivalent of 45*78 of the actual size = 3510 inches. The same can be applied to the height. Multiplying 26 x 78, the actual size should have a height of 2028 inches.

8 0

3 years ago

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be

babymother [125]

Answer:

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

8 0

3 years ago

How do you solve a/7+5/7=2/7

Anton [14]

$\frac{a}{7} + \frac{5}{7} = \frac{2}{7} \\ \frac{a + 5}{7} = \frac{2}{7} \\ 7(\frac{a + 5}{7}) = 7(\frac{2}{7})$
a + 5 = 2
a + 5 - 5 = 2 - 5
a = -3

Hope this helps! :)

4 0

4 years ago

-6x-14y=16 and -2x+7y=17 solve by elimination show the work

professor190 [17]

Answer:

(- 5, 1 )

Step-by-step explanation:

- 6x - 14y = 16 → (1)

- 2x + 7y = 17 → (2)

Multiplying (2) by - 3 and adding to (1) will eliminate the x- term

6x - 21y = - 51 → (3)

Add (1) and (3) term by term to eliminate x

0 - 35y = - 35

- 35y = - 35 ( divide both sides by - 35 )

y = 1

Substitute y = 1 into either of the 2 equations and solve for x

Substituting into (1)

- 6x - 14(1) = 16

- 6x - 14 = 16 ( add 14 to both sides )

- 6x = 30 ( divide both sides by - 6 )

x = - 5

solution is (- 5, 1 )

6 0

2 years ago