Answer:
f(g(-64)) = -190
Step-by-step explanation:
The functions are not well written.
Let us assume;
f(x) = x+1
g(x) = 3x+1
f(g(x)) = f(3x+1)
Replace x with 3x+1 in f(x)
f(g(x)) = (3x+1) + 1
f(g(x)) = 3x + 2
f(g(-64)) = 3(-64) + 2
f(g(-64)) = -192+2
f(g(-64)) = -190
<em>Note that the functions are assumed but same method can be employed when calculating composite functions</em>
Answer:
Step-by-step explanation:
Ask your teacher
Use the Pythagorean theorem, tan is y/x so y = -3 and x= -2. Because cos is negative and R is always positive. You need to find R- which is the hypotenuse;
3^2 + 2^2 = r^2
9 + 4 = r^2
13 = r^2
√13 = r.
So you already have tan<span>θ,
cot</span><span>θ= 2/3
sin</span>θ= -3/√13 BUT
you have to rationalize, so you get -3 √13/ 13
cscθ= √13/ -3
cosθ= -2/ √13 BUT
you have to rationalize, so you get -2√13/ 13
secθ= √13/ -2
Let, S = Shirt, J = Jeans
14a)
This question asks for the discount to be added after everything else.
S= 12 J=19
3S + 2J -3 = Cost with discount applied to total
^ This expression adds to costs, then takes away the $3 discount as the end.
14b)
This questions says the discount is added on every shirt, we get a similar expression:
3(S-3) + 2(J-3) = Cost with discount applied on every shirt and jeans
14c)
The difference between a) and b) is that:
> the discount in a) is applied on the total, meaning a lower discount
> the discount for b) is applied on each shirt and jeans, meaning a greater discount
14d)
If I were the shop owner I would be more specific of what the discount included, for example we don't know whether to discount each product (shirts and jeans) or only discount the total.
