Answer:
the number of protons in the nuclues of an atom
The value of the function 1) f -g = 2x² - 3x + 6 and 2) f(g(2)) is 3.
Here the two functions are given, f(x) and g(x).
f(x) = 2x² + 1
g(x) = 3x - 5
We have to find f-g and f(g(2)).
1) f- g
f(x) - g(x)
(2x² + 1) - ( 3x - 5)
2x² + 1 - 3x + 5
2x² - 3x + 6
2) f(g(2))
f(g(x)) = 2(3x-5)² + 1
= 2( 9x² - 30x + 25) + 1
= 18x² - 60x + 50 + 1
= 18x² - 60x + 51
f(g(2)) = 18(2)² - 60(2) + 51
=18× 4 - 120 + 51
= 72 - 120 + 51
= 123 - 120
= 3
Therefore the value of f-g is 2x²- 3x + 6 and the value of f(g(2)) is 3.
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If both polynomials are the same degree, divide the coefficients of the highest degree terms. If the polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote<span>.</span>The curves approach these asymptotes but never cross them. To find the vertical asymptote(s) of a rational function, simply set the denominator equal to 0 and solve for x.Finding Slant Asymptotes<span> of Rational Functions.
A </span>slant (oblique) asymptote occurs<span> when the polynomial in the numerator is a higher degree than the polynomial in the denominator. To </span>find the slant asymptote<span> you must divide the numerator by the denominator using either long division or synthetic division.
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