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3 years ago

What is the factored form of 64g^3+8?

1 answer:

7 0

64 = 4 x 4 x 4 g^3 = g x g x g the problem is the sum of of 2 cubes 8 = 2 x 2 x 2 so the factored form is - a3+b3=(a+b)(a2−ab+b2).

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What is 11.375 in faction

Anton [14]

11 3/8 would be the simplified version and 91/8 would be the other way.

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3 years ago

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14 divided 3/11 +14 x

slamgirl [31]

Answer:

14x+14/33

Step-by-step explanation:

14÷3/11+14x=

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3 years ago

Solve the equation 9=h/9

abruzzese [7]

ANSWER: h=1

EXPLANATION: I hope I help

8 0

3 years ago

Glen got 48 out of 64 correct in his test.

kati45 [8]

Answer:

He got 16 incorrect

Step-by-step explanation:

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3 years ago

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A geometric sequence is defined by the equation an = (3)3 − n.

Delvig [45]

PART A

The geometric sequence is defined by the equation

$a_{n}=3^{3-n}$

To find the first three terms, we put n=1,2,3

When n=1,

$a_{1}=3^{3-1}$

$a_{1}=3^{2}$

$a_{1}=9$
When n=2,

$a_{2}=3^{3-2}$
$a_{2}=3^{1}$

$a_{2}=3$

When n=3

$a_{3}=3^{3-3}$

$a_{3}=3^{0}$
$a_{1}=1$
The first three terms are,

$9,3,1$

PART B

The common ratio can be found using any two consecutive terms.

The common ratio is given by,
$r= \frac{a_{2}}{a_{1}}$
$r = \frac{3}{9}$

$r = \frac{1}{3}$

PART C

To find
$a_{11}$

We substitute n=11 into the equation of the geometric sequence.

$a_{11} = {3}^{3 - 11}$

This implies that,

$a_{11} = {3}^{ - 8}$

$a_{11} = \frac{1}{ {3}^{8} }$

$a_{11}=\frac{1}{6561}$

4 0

3 years ago