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RoseWind [281]
3 years ago
9

Find the error & find the correct answer 2In(x)=In(3x)-[In(9)-2In(3)] In(x^2)=In(3x)-[In(9)-In(9)] In(x^2)=In(3x)-0 In(x^2)=

In(3x/0); division by 0, undefined
Mathematics
1 answer:
Art [367]3 years ago
4 0

Answer:

Error:lnx^2=ln 3x not ln\frac{3x}{0}

Solution:x=0 and 3

Step-by-step explanation:

We have to find the error and correct answer

Given:2ln x=ln(3x)-[ln9-2ln(3)]

lnx^2=ln(3x)-[ln9-ln3^2]

Using the formula

alog b=logb^a

lnx^2=ln(3x)-[ln9-ln9]

lnx^2=ln(3x)-0

lnx^2=ln(3x)

x^2=3x

x^2-3x=0

x(x-3)=0

Therefore, x=0 and x=3

But last step in the given solution

lnx^2=ln\frac{3x}{0}=\infty

It is wrong this property is used when

log m-log n then

log\frac{m}{n}

Hence, the student wrote  lnx^2=ln\frac{3x}{0}instead of lnx^2=ln3x and solution is given by

x=0 and x=3

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Answer:

Ok, so the equation would be 6-2*12+5. The answer to that is -13.

Step-by-Step Explanation:

You would use PEMDAS. First, you multiply 2 and 12 and that's 24. Now your equation is 6-24+5. Then you subtract 6 and 24 and that's -18. Now your equation is -18+5, and the answer to that equation is -13. I hope this helps you!!

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2 years ago
The product of 2 √3 and 3 √12 simplified form is...
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<h2>Greetings!</h2><h3>When multiplying two roots together, you can rearrange the equation so that the roots are next to each other and so are the whole numbers:</h3>

2 x 3 x \sqrt{3} x \sqrt{12}

<h3>This means that 2 x 3 is simple, = 6,</h3><h3>But when multiplying \sqrt{3} x \sqrt{12} you simply multply the two numbers and put them in a square root:</h3>

\sqrt{3} x \sqrt{12} = \sqrt{36}

<h3>But this can be square rooted to 6, which then means that the equation is now:</h3>

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3 years ago
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Step-by-step explanation:

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7 0
3 years ago
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X=12
Hope this helps

3 0
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Solve for x<br> A)9<br> B)33<br> C)45<br> D)62
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Answer:

A) 9

Step-by-step explanation:

R=7x+17

S=4x-6

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