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3 years ago

Can you check my answer?

1 answer:

4 0

The rate of change is another way of saying slope
since the total text messages increase by 35 each day the slope (rate of change) should be 35

Way to prove it if slope isn't as obvious:

since you have the day and the total text messages you can use day as x and total text messages as y giving you the coordinates of: (1,35) (2,70) (3,105)

then you can use the slope formula to find the slope
m= (y₂-y₁)/(x₂-x₁) and pick two coordinates to plug in

I choose coordinates (1,35) and (2,70) to plug into the equation
m=(70-35)/(2-1)
m=35/1
m=35
so the rate of change is 35

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The amount or the strength of force is called its

coldgirl [10]

The amount or the strength of force is named magnitude.

<h3>What is force?</h3>

Force is that the push or pull on an object with mass that causes it to alter its velocity. Force is an external agent capable of adjusting the state of rest or motion of a selected body. it's a magnitude and a direction.

<h3 /><h3>How to identify strength of force?</h3>

The term which is true is magnitude. The magnitude of a force is expressed within the SI unit of force called Newton. 1 Newton is that the force which might make an object of 1 kilogram mass to at a speed of 1 meter per second. Magnitude is essentially the most extent of size and also the direction of an object. Magnitude is employed as a typical think about vector and scalar quantities. Magnitude of earthquake is measured by Richter scale.

Hence the number or the strength of force is named its magnitude.

Learn more about force at brainly.com/question/12970081

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5 0

2 years ago

Read 2 more answers

De acuerdo con la tercera ley de movimiento planetario de Kepler, la masa de un planeta es directamente proporcional al cubo de

Sunny_sXe [5.5K]

Answer:

La masa del Sol es $2.509\times 10^{31}$ kilogramos.

Step-by-step explanation:

Tras una lectura cuidadosa al enunciado, tenemos que la Tercera Ley de Kepler queda descrita por la siguiente relación:

$M \propto \frac{r^{3}}{T^{2}}$

$M = k\cdot \frac{r^{3}}{T^{2}}$ (Eq. 1)

Donde:

$r$ - Distancia entre los centros del planeta y el satélite, medido en kilómetros.

$T$ - Período oribital del satélite, medido en días.

$k$ - Constante de proporcionalidad, medida en kilogramo-días cuadrados por kilómetro cúbico.

$M$ - Masa del planeta, medida en kilogramos.

Podemos obtener la masa del Sol mediante la siguiente relación:

$\frac{M_{S}}{M_{E}} = \frac{\frac{r_{E}^{3}}{T_{E}^{2}} }{\frac{r_{M}^{3}}{T_{M}^{2}} }$

$\frac{M_{S}}{M_{E}} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}$ (Eq. 2)

Donde:

$T_{M}$ , $T_{E}$ - Períodos orbitales de la Luna y la Tierra, medidos en días.

$r_{E}$ , $r_{M}$ - Distancias entre la Tierra y el Sol, así como entre la Luna y la Tierra, medidas en kilómetros.

$M_{S}$ , $M_{E}$ - Masas del Sol y la Tierra, medidos en kilogramos.

Si $M_{E} = 75.97\times 10^{24}\,kg$ , $T_{E} = 365.3\,d$ , $T_{M} = 27.3\,d$ , $r_{M} = 3.84\times 10^{5}\,km$ y $r_{E} = 1.496\times 10^{8}\,km$ , entonces tenemos que la masa del Sol es:

$M_{S} = \left(\frac{T_{M}}{T_{E}} \right)^{2}\cdot \left(\frac{r_{E}}{r_{M}} \right)^{3}\cdot M_{E}$

$M_{S} = \left(\frac{27.3\,d}{365.3\,d} \right)^{2}\cdot \left(\frac{1.496\times 10^{8}\,km}{3.84\times 10^{5}\,km} \right)^{3}\cdot (75.97\times 10^{24}\,kg)$