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deff fn [24]
3 years ago
10

Write an expression with four terms. Include at least one term with an exponent, one term with a coefficient of 5, one term with

three factors, and one constant. Make two of the terms like terms.
Mathematics
1 answer:
Leokris [45]3 years ago
8 0
An algebraic expression is looking something like this: 8x³ + 5
This expression has two terms; 8x³ and 5
The value of '8' in 8x³ is called COEFFICIENT
The value of '3' in 8x³ is called POWER or INDICES
The term 8x³ is called  an exponent because it has power/indices
The letter 'x' in the term 8x³ is called VARIABLE

So, we want an expression with four terms
_____ ⁺/₋ _____ ⁺/₋ _____ ⁺/₋ _____

One term with an exponent ⇒ You can choose any letter and any power that will go with it, for example, 6x⁴

One term with a coefficient of 5 ⇒ 5x⁴

One term with three factors ⇒ This could be a combination of any three letters that represent three values for example 'abc'. This term means a × b × c, so it has three factors.

One constant ⇒ Choose any number, say 45

Make two of the terms like terms ⇒ We have 6x⁴ + 5x⁴; these two terms are alike, they are in term of x⁴

Putting the four terms together: 6x⁴ + 5x⁴ + abc + 45
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2 years ago
A study was conducted to determine the proportion of American teenagers between 13 and 17 who smoke. Previous surveys showed tha
timofeeve [1]

Answer:

The study only provides evidence that the percentage of teenagers who smoke is different than 15% but only considering teenagers between 13 and 17.

Step-by-step explanation:

I will assume that when we talk about a teenager, we are talking about a teenager between 13 and 17 years old. We can solve this problem with a hypothesis test. Lets first define the main hypothesis of our test and the alternate hypothesis, note that 70 is way less than 15% of 785 (is less than 10%), thus we can use the following ones

H0: 15% of the teenagers smoke

H1: Less than 15% of teenagers smoke

Lets rewrite H0 and H1 using probabilities. Let X be the amount of teenagers that smoke in a sample with length 785. X is a binomial random variable. If we take H0 to be true, then the probability of success in each individual outcome of X is 0.15. This means that the mean is μ = 0.15*785 = 117.75, and the standard deviation is σ = √(117.75(1-0.15)) = 10.00437.

Since we are working with a sample of length high enough (> 30), then the Central Limit Theorem tells us that X behives pretty similar to a Normal random variable, with similar mean and standard deviation; therefore, we may assume directly that X is normal.

The hypothesis can be rewritten in terms of X this way:

H0: μ = 117.75 (this means that in average 15% of a sample of 785 smoke)

H1: μ < 117.75

We will use a 95% confidence interval. note that if only 70 teenagers smoke, then that means that SX = 70, where SX is the sample we obtain. We will calculate the probability that X is less than (or equal) to 70, if that probability is less than 0.05, then we can say that we have evidence that the percentage of teenagers who smoke is different (in fact, less), than 15%.

In order to calculate P(X < 70), we will use the standarization of X, given by

W = \frac{X-\mu}{\sigma} = \frac{X-117.75}{10.00437}

The cummulative distribution function of W, which we denote \phi has well known values and they can be found in the attached file. Also, since the density function of a standard random normal variable is symmetric, then we have that \phi(-x) = 1-\phi(x) for any positive value x.

P(X < 70) = P(\frac{X-117.75}{10.00437} < \frac{70-117.75}{10.00437}) = P(W< -4.772914) = \phi(-4.772914) = 1-\phi(4.772914)

If we look at the table, we will realise that \phi(4.772914) is practically 1, thus P(X < 70) is practically 0 if we assume that the mean of X is 117.75.

This means that we have evidence that the percentage of teenagers who smoke is no longer 15%, it is less.

However, here we are assuming that the term 'teenager' and teenager between 13 and 17' is the same. Maybe the the study took teenagers with 20 years old or so, and if that happened, then it makes sense that the results here are not the same. Therefore, we conclude that the study only provides evidence that the percentage of teenagers who smoke is different than 15% but only considering teenagers between 13 and 17 (because that is where the sample came from).

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7 0
3 years ago
Suppose f(x)=2x−5. Find the value of f(3)<br><br> can someone please help me with this?
dmitriy555 [2]

f(3) = 1

substitute x = 3 into f(x)

f(3) = (2 × 3) - 5 = 6 - 5 = 1


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Can somebody help me please ?
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Answer:

ik that angle one would be the same as 3 and 2 and 4 are also the same so if u find an answer for 2 or 4 they would be the same but is there like a total of the entire thing

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