Answer:
A. The solution set is x = 5 or -7
Step-by-step explanation:
![\sqrt[4]{ {x}^{2} + 2x } = \sqrt[4]{35} \\ {({x}^{2} + 2x) }^{ \frac{1}{4} } = {(35)}^{ \frac{1}{4} } \\ {x}^{ \frac{1}{2} } + {2x}^{ \frac{1}{4} } = {35}^{ \frac{1}{4} } \\ {x}^{2} + 2x = 35 \\ {x}^{2} + 2x - 35 = 0 \\ (x - 5)(x + 7) = 0 \\ x = 5 \: or \: - 7](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20%7Bx%7D%5E%7B2%7D%20%2B%202x%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B35%7D%20%20%5C%5C%20%7B%28%7Bx%7D%5E%7B2%7D%20%2B%202x%29%20%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%3D%20%20%7B%2835%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%5C%5C%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20%2B%20%7B2x%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%20%3D%20%20%7B35%7D%5E%7B%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%5C%5C%20%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%3D%2035%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%20-%20%2035%20%3D%200%20%5C%5C%20%28x%20-%205%29%28x%20%2B%207%29%20%3D%200%20%5C%5C%20x%20%3D%205%20%20%5C%3A%20or%20%5C%3A%20%20-%207)
Therefore, the answer is A. as the solution is x = 5 or -7
A linear equation is an equation between two variables that gives a straight line when plotted on a graph.
Answer:
56 degrees
Step-by-step explanation:
Hello there!
Remember the sum of the angles in a triangle is equal to 180
so to find the missing angle we subtract the given angles from 180
180 - 34 - 90 = 56
so we can conclude that the measure of the missing angle is 56 degrees
Note: the little square at the bottom left of the triangle indicates that the angle is a right angle. The measure of a right angle is 90 degrees so thats where the 90 came from
Answer:
Step-by-step explanation:
First, calculate the area of the rectangle.
Here, length = 18 units and Width = 12 units
The formula for calculating the area of the rectangle is 
The radius of the semi-circle is 6 units.
The formula for calculating the area of the semi-circle is 
.
The area of the shaded region is equal to the difference of area of the rectangle and area of the semi-circle.
Use y2-y1/x2-x1
So 0-5/3-2
-5/1= m= -5
Then plug it into y=MX+B
0= -5(3)+b
0= -15+b
b=15
y=-5x+15
So I hope this helps but I'm not sure how to plug it into that's equation. The rest of my work is rigt
