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mihalych1998 [28]
3 years ago
15

Trigonometry: If f(x)= 2sinx + cosx using exact values find f (120 degrees). if possible show steps.

Mathematics
1 answer:
Arada [10]3 years ago
3 0

Answer: f(120°) = (√3) + 1/2

Step-by-step explanation:

i will solve it with notable relations, because using a calculator is cutting steps.

f(120°) = 2*sin(120°) + cos(120°)

           =2*sin(90° + 30°) + cos(90° + 30°)

here we can use the relations

cos(a + b) = cos(a)*cos(b) - sin(a)*sin(b)

sin(a + b) = cos(a)*sin(b) + cos(b)*sin(a)

then we have

f(120°) = 2*( cos(90°)*sin(30°) + cos(30°)*sin(90°)) +  cos(90°)*cos(30°) - sin(90°)*sin(30°)

and

cos(90°) = 0

sin(90°) = 1

cos(30°) = (√3)/2

sin(30°) = 1/2

We replace those values in the equation and get:

f(120°) = 2*( 0 +  (√3)/2) + 0 +  1/2 = (√3) + 1/2

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Ariele is hiking down into the canyon. She starts at the rim and hikes down 55 feet in 234 minutes. If she continues at this rat
Aleksandr-060686 [28]

Answer:

This means that she will be 16.35 ft away from the rim in 15 minutes at this current rate.

Step-by-step explanation:

What we are asked here is imply to state how long in terms of distance would be Arielle position after 15 minutes

Now, 55 ft will take her 234 minutes

x ft will take her 15 minutes

x * 234 = 55 * 15

234x = 3825

x = 3825/234

x = 16.35 ft

This means that she will be 16.35 ft away from the rim in 15 minutes at this current rate.

7 0
3 years ago
The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c
timurjin [86]

Answer:

a) 28

b)

Class Limits  Class Boundaries   Midpoint    f      Rf         Cf

10 - 37            9.5-37.5                   23.5            7     0.096     7      

38 - 65           37.5-65.5                 51.5           25    0.342     32    

66 - 93           65.5-93.5                 79.5          26    0.356     58    

94 -  121        93.5-121.5                   107.5         9     0.123       67    

122 - 149      121.5-149.5                  135.5         5      0.068     72  

150 - 177       149.5-177.5                  163.5        0         0.0      72    

178 - 205       177.5-20.5                  191.5         1       0.014      73  

Total                                                                  73          1.0    

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx
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