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qaws [65]
3 years ago
5

It takes 25 minutes to fry a burger at Jill street, how long will it take to fry 13 burgers​

Mathematics
2 answers:
Misha Larkins [42]3 years ago
7 0

Answer:

325 minutes

Step-by-step explanation:

We can use a ratio to solve

25 minutes         x  minutes

------------------  = ---------------

1 burger                   13 burgers

Using cross products

25*13 = 1x

325 = x

325 minutes

stellarik [79]3 years ago
5 0

Answer:

325 minutes <em>or </em> 5 hours and 25 minutes

Step-by-step explanation:

If it takes 25 minutes to fry a single burger, assuming only one burger can be made at a time, you must multiply the time per burger by how many burgers are made. So. 25(13) = 325 minutes <em>or</em> 5 hours and 25 minutes.

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Amelia has 3 gallons of paint .Mason have 10 quarts .How many more pints of paint does AMELIA have then mason.
Ber [7]

Answer:

4 Pints

Step-by-step explanation:

According to the scenario, calculations are as follows,

As we know, 1 gallon = 8 Pints

1 Quarts = 2 Pints

So, Amelia = 3 Gallons = 3 × 8 Pints = 24 Pints

Mason = 10 quarts = 10 × 2 Pints = 20 Pints

So, Number of more pints Amelia has = Amelia number of pints - Mason number of pints

= 24 pints - 20 pints

= 4 Pints  

6 0
3 years ago
Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join
zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx  = 1

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y)  and replacing a and b with their respective values, we have

\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx  = 1

Since c is a constant, we can bring it out of the integral sign; to give us

c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx  = 1

Open the bracket

c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx  = 1

Integrate with respect to y

c\int\limits^3_0 {\frac{xy^{2}}{2}  +\frac{xy^{3}}{3} } \, dx (0,3}) = 1

Substitute 0 and 3 for y

c\int\limits^3_0 {(\frac{x* 3^{2}}{2}  +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2}  +\frac{x * 0^{3}}{3})} \, dx = 1

c\int\limits^3_0 {(\frac{x* 9}{2}  +\frac{x * 27}{3} ) - (0  +0) \, dx = 1

c\int\limits^3_0 {(\frac{9x}{2}  +\frac{27x}{3} )  \, dx = 1

Add fraction

c\int\limits^3_0 {(\frac{27x + 54x}{6})  \, dx = 1

c\int\limits^3_0 {\frac{81x}{6}  \, dx = 1

Rewrite;

c\int\limits^3_0 (81x * \frac{1}{6})  \, dx = 1

The \frac{1}{6} is a constant, so it can be removed from the integral sign to give

c * \frac{1}{6}\int\limits^3_0 (81x )  \, dx = 1

\frac{c}{6}\int\limits^3_0 (81x )  \, dx = 1

Integrate with respect to x

\frac{c}{6} *  \frac{81x^{2}}{2}   (0,3)  = 1

Substitute 0 and 3 for x

\frac{c}{6} *  \frac{81 * 3^{2} - 81 * 0^{2}}{2}    = 1

\frac{c}{6} *  \frac{81 * 9 - 0}{2}    = 1

\frac{c}{6} *  \frac{729}{2}    = 1

\frac{729c}{12}    = 1

Multiply both sides by \frac{12}{729}

c    =  \frac{12}{729}

c    =  0.0165 (Approximately)

8 0
3 years ago
Square root of 19.4 rounded to the nearest hundredth
photoshop1234 [79]

Answer:

there is none.

Step-by-step explanation:

19.4, the lowest is tenths, you need another digit down for hundredths.

hope I helped!

5 0
3 years ago
Please help!! Will get brainliest! Zoom if can’t see. Correct answer only!!
8090 [49]
Domain = Set of all real numbers, which is choice B
Range = Choice C) y \le 3

The domain is the set of allowed x value inputs of a function. In this case, we can plug in any x value we want. The graph stretches forever in both directions along the x axis. This is shown by the arrows.So that's why the domain is the set of all real numbers.

The range is the set of outputs of a function. It is the set of possible y values. As you can see on the graph, the highest point is at (-1,3) which is the vertex.
The largest y value possible is y = 3. Any other y value smaller than this is possible. So the range is therefore y \le 3 where y is a real number


7 0
3 years ago
A spinner is divided into 8 equal sections, and each section contains a number from 1 to 8. What is the probability of the spinn
Elodia [21]

Answer:

StartFraction 1 over 8 EndFraction

Step-by-step explanation:

It would be 1/8 because there is 8 sections on the spinner and 5 is on 1 section of the spinner so it would 1/8.

8 0
3 years ago
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