WILL MARK YOU AS BRAINLIEST HELP PLZ

When k=7 and q=35 find the value of p in direct proportion method

Arisa [49]

I think the answer is 5.

y = kx is the equation for direct proportionality. I’m guessing your “q” is the “y”, because 35 is easily divisible by 7.

35 = 7x
x = 5

7 0

3 years ago

Could someone help pls

Anna007 [38]

Answer:

40%

Step-by-step explanation:

6/15=favorable amount/total amount

6/15=2/5

2/5*20

8 0

3 years ago

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A certain company sends 40% of its overnight mail parcels by means of express mail service A1. Of these parcels, 4% arrive after

Harrizon [31]

Answer:

(a) The probability that a randomly selected parcel arrived late is 0.026.

(b) The probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c) The probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d) The probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

Step-by-step explanation:

Consider the tree diagram below.

(a)

The law of total probability sates that: $P(A)=P(A|B)P(B)+P(A|B')P(B')$

Use the law of total probability to determine the probability of a parcel being late.

$P(L)=P(L|A_{1})P(A_{1})+P(L|A_{2})P(A_{2})+P(L|A_{3})P(A_{3})\\=(0.04\times0.40)+(0.01\times0.50)+(0.05\times0.10)\\=0.026$

Thus, the probability that a randomly selected parcel arrived late is 0.026.

(b)

The conditional probability of an event A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

Compute the probability that a parcel was late was being shipped through the overnight mail service A₁ as follows:

$P(A_{1}|L)=\frac{P(L|A_{1})P(A_{1})}{P(L)} \\=\frac{0.04\times 0.40}{0.026} \\=0.615$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₁ is 0.615.

(c)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{2}|L)=\frac{P(L|A_{2})P(A_{2})}{P(L)} \\=\frac{0.01\times 0.50}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₂ is 0.192.

(d)

Compute the probability that a parcel was late was being shipped through the overnight mail service A₂ as follows:

$P(A_{3}|L)=\frac{P(L|A_{3})P(A_{3})}{P(L)} \\=\frac{0.05\times 0.10}{0.026} \\=0.192$

Thus, the probability that a parcel was late was being shipped through the overnight mail service A₃ is 0.192.

4 0

3 years ago

a mountaineer climbed 1,000 feet at a rate of x feet per hour, he climbed and additional 5,000 feet at a different rate. this ra

marshall27 [118]

A mountaineer climbed 1000 feet at a rate of x feet/hour

1000 = x ( t 1 ) eq1

5000 = X ( t 2) eq2 ( he climbed additional at different rate )

the rate was 10 feet / hour less than twice the first rate

X = 2x - 10 eq3

take eq1 and eq 2

( total time = t 1 + t 2 = T)

T = 1000/x + 5000/X

but X = 2x-10

T = 1000/x + 5000/( 2x -10)

T = 1000/x + 5000/( 2(x-5))

T = 1000/x + 2500 / (x-5)

3 0

3 years ago

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Greg drew a pair of parallel lines and a line segment next to each other on a chalkboard. Which of these statements best compare

Novosadov [1.4K]

<span>The parallel lines extend infinitely in both directions, and the line segment has two endpoints. </span>

8 0

4 years ago

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