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HACTEHA [7]
2 years ago
13

WILL GIVE BRAINLIEST!

Mathematics
1 answer:
finlep [7]2 years ago
6 0

Answer:

  XF·XG = 17

Step-by-step explanation:

Drawing a cyclic quadrilateral from side lengths is interesting enough. I have no idea how to compute the desired value, but my geometry program says it is 17.

In the attached, XF is line segment m, approximately 7.63 in length. XG is line segment n, approximately 2.23 in length. The product is the number "o", shown at the end of the red arrow.

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Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
HELP!!!! I WILL GIVE BRAINLIEST TO THE FIRST ANSWER!!!!!!!
aleksklad [387]
I would say c. I’m not sure if I’m right if I’m not sorry but good luck
3 0
3 years ago
Find the least common denominator (lcd) of 1/3 and 2/9 .
OLEGan [10]
The lowest common denominator of 1/3 and 2/9 = 9
8 0
3 years ago
-8(x + 1) + 3(x - 2) = -3x + 2?
alexira [117]
First you need to distribute the -8
So you would get -8x-8 now distribute the 3 so it would be 3x-6
-8x-8+3x-6=-3+2 is how it should look
Now combine the -8x and 3x cause their like terms and also -8 and -6
-5x-14=-3x+2 now add -3 to both sides
-2x-14=2 and add 14 to both sides
-2x=12 all left to do is divide both by -2
X=-6
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3 years ago
Conner works 8 1/2 hours and earns $80.75. If Zoey makes an hourly rate that is proportional and earns $118.75, how many hours d
Romashka-Z-Leto [24]
Hopes this helps below if it did please say thanks on the button or make me the brainiest:)

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