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k0ka [10]
3 years ago
7

A swimming pool is open for 7 1/2 hours a day. The pool kepps one lifeguard at a time and each lifeguard shift is 1 1/2 hous lon

g. How many shifts are ther per day?
Mathematics
1 answer:
vredina [299]3 years ago
5 0
(7 1/2)/(1 1/2)=5 
so there will be 5 shifts per hour.
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Find a formula for the nth term of the arithmetic sequence first term -17 common difference 5
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Given :-

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To Find :-

  • The formula for the nth term .

Solution :-

We know that the nth term of an AP is given by ,

T_n = a +(n-1)d

where ,

  • a is the First term .
  • n is the number of the term .
  • d is the common difference .
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On substituting the respective values we have ,

T_n = -17 + (n -1)5 \\

Open the brackets ,

T_n = -17 + 5n - 5

Simplify ,

T_n = 5n -22

<u>Hence</u><u> the</u><u> </u><u>nth </u><u>term</u><u> of</u><u> </u><u>the</u><u> </u><u>AP </u><u>is </u><u>given</u><u> </u><u>by </u><u>5</u><u>n</u><u> </u><u>-</u><u>2</u><u>2</u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>

5 0
3 years ago
On a scale drawing, the scale is 1 inch = 1 foot. Find the scale factor.
balu736 [363]
The answer is 1:12 or 1/12
3 0
4 years ago
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Sorin hits a cricket ball straight up into the air. After 1.5s, the ball is falling straight down with a speed of 6.5 m/s. We wa
sveticcg [70]

Step-by-step explanation:

We have, Sorin hits a cricket ball straight up into the air. After 1.5 s, the ball is falling straight down with a speed of 6.5 m/s.

We want to find the initial vertical velocity of the ball.

The relation between initial speed, final speed, acceleration and time is given by using first equation of kinematics. Let v₀ is the initial speed. So,

v=v_o +at

Here, v = -6.5 m/s, t = 1.5 s and a = -g

v_o=v-at\\\\v_o=v+gt\\\\v_o=-6.5+9.8\times 1.5\\\\v_o=8.2\ m/s

So, the initial velocity of the ball is 8.2 m/s and the formula used is (1).

4 0
4 years ago
Given the diagram, solve for the blanks below:
zmey [24]

Answer:

AC》12

FC》6

Step-by-step explanation:

hope it helps..

have a great day.

4 0
3 years ago
Graph the quadratic functions y=-2xandy=-2x2 + 4 on a separate piece of paper. Using those graphs, compare and contrast the shap
dedylja [7]

Y = -2x^2

h = Xv = -B/2A = 0/-4 = 0.

k = -2*0^2 = 0.

V(0,0).

Use the following points for graphing:

Y = -2x^2.

(x,y)

(-2,-8)

(-1,-2)

V(0,0)

(1,-2)

(2,-8)

Y = -2x^2 + 4.

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k = Yv = -2*0^2 + 4 = 4.

V(0,4).

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(-1,2)

V(0,4)

(1,2)

(2,-4)

8 0
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