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Mumz [18]
3 years ago
10

One year there was a total of 58 commercial and noncommercial orbital launches worldwide. In​ addition, the number of noncommerc

ial orbital launches was twomore than three times the number of commercial orbital launches. Determine the number of commercial and noncommercial orbital launches.
Mathematics
2 answers:
GuDViN [60]3 years ago
6 0
Noncommercial: 30 orbital launches
Commercial : 28 orbital launches
Ksivusya [100]3 years ago
6 0
I am 100 present sure the other person is right ;D
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If by 4x(2) you mean 4x to the power 2 or 4x^2...it can be solved in the following way
f(x)=4x^2-4x-3
=4x^2+2x-6x-3
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=(2x-3)(2x+2)
Therefore x=3/2 or x=-2/2=(-1)
8 0
3 years ago
Ronald saves 10.00 to buy a new book. The book original price was 15 but it was on sale for 35% off with a 6% sales tax. Does he
Lady bird [3.3K]
$6.89

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2 years ago
A hot air balloon is released at ground level and it rises into the air at a constant rate . after 5 second the height of the ba
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Answer:It's d

Step-by-step explanation:

8 0
3 years ago
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
PLEASE HELP ME
omeli [17]

Step-by-step explanation:

it will take you 15 minutes

7 0
3 years ago
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