Let
x------> amount of pounds of apples
y------> amount of pounds of oranges
z-----> amount of pounds of peaches
we know that
x+y+z=127------> equation 1
x=4z-----> equation 2
y=7+z----> equation 3
substitute equation 2 and equation 3 in equation 1
x+y+z=127----> (4z)+(7+z)+z=127---> 6z=127-7---> 6z=120----> z=20 lb
x=4z---> x=4*20----> x=80 lb
y=7+z----> y=7+20---> y=27 lb
amount of pounds of apples----> 80 lb
amount of pounds of oranges----> 27 lb
amount of pounds of peaches---> 20 lb
Answer:
I think its 2!
Step-by-step explanation:
Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: 
Therefore, 
Variance of binomial random variable: 
Therefore, 
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.