Answer:
Step-by-step explanation:
(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.
(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.
(C) Example of a second order linear ODE:
M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)
The equation will be homogeneous if K(t)=0 and heterogeneous if 
Example of a second order nonlinear ODE:
(D) Example of a nonlinear fourth order ODE:
![K^4(x) - \beta f [x, k(x)] = 0](https://tex.z-dn.net/?f=K%5E4%28x%29%20-%20%5Cbeta%20f%20%5Bx%2C%20k%28x%29%5D%20%3D%200)
Answer:
-15a² -14a+16
Step-by-step explanation:
<h2>(2-3a)(8+5a)</h2>
2×8=16
2×5a=10a
-3a×8=-24a
-3a×5a=-15a²
16+10a-24a-15a² = -15a² -14a+16
Answer:
Area of Large Circle = 380.13
Area of Small Circle = 254.47
Area of Sidewalk = 125.66
Step-by-step explanation:
The side walk is just subtracting the smaller number from the bigger one.
The area is just Pi*r^2
Answer:
Initial height of the anchor is 75 meters.
Step-by-step explanation:
We are given the following in the question:
where, I is the anchor's elevation in meter after t seconds dropped from the ship.
We have to find the initial height of anchor that is we have to put t = 0 in the equation.
Putting t = 0, we get,
Thus, initial height of the anchor is 75 meters.
6 seconds = 540 m
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Find 1 second:
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6 sec = 540 m
1 sec = 540 ÷ 6
1 sec = 90m
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Find 4 seconds:
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1 sec = 90m
4 sec = 90 x 4
4 sec = 360 m
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Answer: It can travel 360m in 4 seconds.
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