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Talja [164]
3 years ago
6

Is this set closed or not closed under the operation ? Negative integers under multiplication

Mathematics
1 answer:
Romashka [77]3 years ago
5 0

The set is not closed

Example:

-4 * -3 = 12  this is not a negative integer

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Guys, help me out, please.
goldfiish [28.3K]

Answer:

4

Step-by-step explanation:

Given

\frac{28}{3+4} ← evaluate the denominator

= \frac{28}{7} ← perform the division

= 4

7 0
2 years ago
A soup can will have a radius of 4 cm and a
DENIUS [597]

Answer:

<h3>            It's about 365 cm²</h3>

Step-by-step explanation:

2×πr² + 2πr×h =

= 2×π×4² + 2π×4×10.5 =

= 32π + 84π =

= 116π ≈

≈ 364.42 cm²

5 0
2 years ago
What is the missing length???
Kaylis [27]

Answer:

25

Step-by-step explanation:

144/60 = 2.4

60/2.4 = x

x = 25

8 0
2 years ago
The data set shows the ages of people riding a bus. What is the mode for this data set? 18 16 11 45 33 11 33 14 18 11
podryga [215]
11 Is the answer I think
3 0
2 years ago
Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
Read 2 more answers
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