Answer:
Explanation:
a) calculate the total avoidable cost in keeping the old machine and buy a new machine:
PARTICULARS KEEP OLD BUY NEW
AMOUNT($) AMOUNT($)
Opportuinty cost of buying 40,000
the old machine
Purchase price 150,000
Operating expenses
(50,000 × 4 years) 200,000
Operating expenses
18,000 × 4 years) 72,000
TOTAL AVOIDABLE COST 240,000 222,000
b)Decision:
Since the cost of operating the new machine is lower,it should be replaced
<span>Which of the following gases would be most likely to experience ideal behavior at high pressures?
a. F2
b. Ne
c. C2H6
Yes. The answer is (b) Ne (Neon). This is because monoatomic gases such as neon do not experience </span><span>intermolecular attractions and thus most likely to be close to ideal gases behavior. Not only that, Neon is a noble gas and is unreactive. </span>
Answer:
1.2 ( two significant digits)
Explanation:
5.4 - 4.21 answer should only have the the number of significant digits as the number in the equation with the least number of significant digits... in this case 5.4 is only two significant digits....so the answer should only have two significant digits
5.4 - 4.21 = 1.19 round to two digits = 1.2
Answer:
66.4g
Explanation:
Given parameters:
Mass of AgNO₃ = 69.1g
Unknown:
Mass of Ag₂CrO₄
Solution:
2AgNO₃+ Na₂CrO₄ ⟶ Ag₂CrO₄ + 2NaNO₃
The given equation is balanced.
To solve this problem, solve from the known to the unknown;
1. Find the number of moles of AgNO₃;
Number of moles =
atomic mass of Ag = 107.9g/mol
N = 14g/mol
O = 16g/mol
Molar mass of AgNO₃ = 107.9 + 14 + 3(16) = 169.9g/mol
Number of moles = = 0.41moles
2. From the balanced equation;
2 moles of AgNO₃ produced 1 moles of Ag₂CrO₄ ;
0.41 moles of AgNO₃ will produce = 0.2moles of Ag₂CrO₄
3:
Mass of Ag₂CrO₄ = number of moles x molar mass
Atomic mass of Ag = 107.9g/mol
Cr = 52g/mol
0 = 16g/mol
Molar mass = 2(107.9) + 52 + 4(16) = 331.8g/mol
so, mass of Ag₂CrO₄ = 0.2 x 331.8 = 66.4g