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amm1812
3 years ago
10

A cotton candy vendor has 30 cones of blue cotton candy to sell. If the blue cotton candy is 75% of the total number of cones, h

ow many total cotton candy cones does he have?
Mathematics
2 answers:
Rzqust [24]3 years ago
8 0
40 cotton candy cones

simplify:  
30/75 (about this, just simplified version)=10/25=40/100

+10 is answer 

40 is final answer
liraira [26]3 years ago
5 0

Answer:

40

Step-by-step explanation:

because its just easy trust me it is !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! i just need points but fr fr its 40

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3) Three times the sum of four and a number is twice the number.
Anna11 [10]

Answer:

3(4+n)=2n

Hope this helps

4 0
3 years ago
Factor. 2v^2-11v-63
Tatiana [17]

Answer:

  (2v +7)(v -9)

Step-by-step explanation:

Factors of 2·(-63) = -126 that have a sum of -11 are 7 and -18, so we can rewrite the middle term to -18v+7v. Then we can factor by grouping.

  2v^2 -18v +7v -63 = 2v(v -9) +7(v -9)

  = (2v +7)(v -9)

5 0
3 years ago
How many ways can you arrange pies on a table in a rectangular array
otez555 [7]
4*5,2*12,in any even number way
4 0
3 years ago
Divide the fractions: 2/3 divided by 3/11
Alina [70]
2/3 ÷ 3/11
flip the second one and multiply:
2/3 × 11/3
22/9
2 4/9

Hope this helps :)
6 0
3 years ago
What is the solution to the following system?
leva [86]

Answer:

(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

\left[\begin{array}{cccc}3&2&1&20\\1&-4&-1&-10\\2&1&2&15\end{array}\right]

Now I will shift rows to make my pivot point (top left) a 1 and so:

\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]

Next I will come up with algorithms that can cancel out numbers where R1 means row 1, R2 means row 2 and R3 means row three therefore,

-2R1+R2=R2 , -3R1+R3=R3

\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]

\frac{R_2}{9}=R_2


\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]


4R2+R1=R1 , -14R2+R3=R3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]


-\frac{9}{20}R_3=R_3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]


-\frac{4}{9}R_3+R_2=R2 , -\frac{7}{9}R_3+R_1=R_1


\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]


Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to".  Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

7 0
3 years ago
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