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amm1812
3 years ago
10

A cotton candy vendor has 30 cones of blue cotton candy to sell. If the blue cotton candy is 75% of the total number of cones, h

ow many total cotton candy cones does he have?
Mathematics
2 answers:
Rzqust [24]3 years ago
8 0
40 cotton candy cones

simplify:  
30/75 (about this, just simplified version)=10/25=40/100

+10 is answer 

40 is final answer
liraira [26]3 years ago
5 0

Answer:

40

Step-by-step explanation:

because its just easy trust me it is !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! i just need points but fr fr its 40

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What is nine plus ten? If you get it right I’ll give you brainliest
Finger [1]

Answer:

19

Step-by-step explanation:

ok is this just a joke?

nine plus ten

9 + 10 = 19

7 0
3 years ago
Solve using quadratic formula<br> 6x^2-x=2
Nadya [2.5K]

6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}

7 0
2 years ago
3. In a single growing season at the Smith Family Orchard, the average yield per apple tree is 150 apples when the number of tre
g100num [7]

Answer:

<em><u>A.10000</u></em>

<em><u>B.25 more trees must be planted</u></em>

Step-by-step explanation:

⇒Given:

  • The intial average yield per acre y_{i} = 150
  • The initial number of trees per acre  t_{i} = 100
  • For each additional tree over 100, the average yield per tree decreases by 1 i.e , if the number trees become 101 , the avg yield becomes 149.
  • Total yield = (number of trees per acre)*(average yield per acre)

<em>A.</em>

⇒If the total trees per acre is doubled , which means :

total number of trees per acre t_{f} = 2*t_{i} = 200

the yield will decrease by : t_{f} - y_{i}

y_{f}= 150-100= 50

⇒total yield = 50*200=10000

<em>B.</em>

⇒to maximize the yield ,

let's take the number of trees per acre to be 100+y ;

and thus the average yield per acre = 150 - y;

total yield = (100+y)*(150-y)\\=15000+50y-y^{2} \\

this is a quadratic equation. this can be rewritten as ,

     ⇒   =15000+50y-y^{2}\\=15000+625 - (625 - 50y +y^{2})\\=15625 - (y-25)^{2}

In this equation , the total yield becomes maximum when y=25;

<u><em>⇒Thus the total number of trees per acre = 100+25 =125;</em></u>

                 

3 0
2 years ago
A circular swimming pool is installed in a rectangular shaped backyard. An underwater light is placed as its center, 16 feet fro
Daniel [21]
What is the question?
8 0
3 years ago
‼️ help with all these questions 20pts + brainliest ‼️
eimsori [14]

Answer:

1) Slope-intercept form

2) 9200

3) 2 months

4) (0,200)

Step-by-step explanation:

A shelter had 200 animals in foster homes at the beginning of spring and the number of animals in foster homes at the end of the summer could be represented by  

y=3000x+200 ............ (1)

Where x is the number of months and y is the number of animals.

1) The equation (1) is written in the slope-intercept form of a straight line equation.

2) After 3 months means x = 3 and the number of animals in the foster home after 3 months will be (3000 ×3 + 200) = 9200 (Answer)

3) Let after x months the animal population will become 6200.

So, 6200 = 3000x + 200

⇒ 3000x = 6000

⇒ x = 2 months (Answer)  

4) If we put x = 0 in equation (1), then we get y = 200.

So, (0,200) is a point on the graph of the line. (Answer)

5 0
3 years ago
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